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nikitadnepr [17]
3 years ago
15

What is (x-2)-(x-5)? Plz I will mark u brainliest.

Mathematics
1 answer:
Olenka [21]3 years ago
7 0

Answer: 3

This is the simplified way

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A french class has a total of 25 student.The number of males is 7 more than the number of females how many males and how many fe
Lady_Fox [76]

Answer:

16 males and 9 females

Step-by-step explanation:

To solve this we can use a system of equations.

Let's start by naming the number of females x.

The number of males would then be y.

<u>Using these variables, we can set up 2 equations using info provided:</u>

A french class has a total of 25 students, -> x+y=25

The number of males is 7 more than the number of females -> x+7=y

Use substitution to solve.

<u>From the second equation:</u>

x+7=y

Subtract 7 from both sides.

x=y-7

Substitute that into the first equation.

x+y=25

y-7+y=25

Combine like terms.

2y-7=25

Add 7 to both sides.

2y=32

Divide both sides by 2.

y=16

Substitute y=16 into equation 2.

x+7=y

x+7=16

Subtract 7 from both sides.

x=9

Therefore, there are 16 males and 9 females in the french class.

3 0
3 years ago
Read 2 more answers
Find the equation of the straight line which passes through (3,5) and makes y-inte<br>r-intercept.​
elixir [45]

Answer:

Please restate your question.

It needs the y-intercept to be decipherable.

Step-by-step explanation:

6 0
3 years ago
Sophia uses 18 beads to make a necklace. Three sixths of the beads are purple. How many beads are purple?
joja [24]

Answer:

9 beads are purple

Step-by-step explanation:

we know that

To find out how many  beads are purple, multiply the total beads by the fraction of the beads that are purple

so

18(\frac{3}{6})=9\ beads

therefore

9 beads are purple

Another way to solve the problem is convert the fraction in percentage

we have

\frac{3}{6}=\frac{1}{2}=0.50*100=50\%

so

If the total are 18 beads

50% is 9 beads

therefore

9 beads are purple

8 0
3 years ago
Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t
Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot  represents class first. From the first box plot, we get

\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

Second box plot  represents class second. From the second box plot, we get

\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

IQR=Q_3-Q-1=89-62=27

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0
3 years ago
Can u please help me with this math assignment
Troyanec [42]
Hard to read sideways but what I got from that is that you have a right triangle and you are trying to explain the other angles? 
Both of the other two angles would be 45 because an angle is 180 total. If it is a right angle, that means that there is a 90 degree angle. 180-90=90. In a right angle, the other two angles are the same in degree. Therefor 90/2 is 45. 45 applies to both of the acute angles. I hope this helps! Good luck :)
6 0
3 years ago
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