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3 years ago

Which organelle if empty would cause the plant to wilt

1 answer:

8 0

The vacuole because the less water it has the more it will wilt. The reason of it wilting is because the cells shrink which is the cause of wilting.

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Which of the following compounds contains the tin (IV) ion? A. SnO2 B. SnCl2 C. Sn2O D. Sn4O3

Zolol [24]

A. SnO2 is the correct answer. I hope this helps

3 0

2 years ago

Read 2 more answers

Which of the following is represented by the number of significant figures in a quantity? A) estimation B) precision C) accuracy

enyata [817]

Answer: the answer is B estimation

Explanation:

i just took a test

4 0

3 years ago

When water is solid, do molecules move?

BabaBlast [244]

Answer:

Ice is water in its solid form. Ice keeps its shape, even if it's removed from the container. The molecules in ice are locked into place and cannot move or slide past one another, but they do vibrate a little bit.

Explanation:

As the temperature drops or decreases, the water molecules gradually slow down. Eventually they stop moving and simply vibrate back and forth. At this point ice is formed, the solid phase of water. If the temperature is allowed to increase, the molecules will once again begin to vibrate faster and faster.

8 0

2 years ago

Read 2 more answers

What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91

Vikentia [17]

Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen $(O_2)$ if it occupies 31.6 mL at $91^{o}C$ .

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

$1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L$

Temperature = $91^{o}C = (91 + 273) K = 364 K$

As molar mass of $O_2$ is 32 g/mol. Hence, the number of moles of $O_2$ are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol$

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

$PV = nRT\\P \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm$

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen $(O_2)$ if it occupies 31.6 mL at $91^{o}C$ .

4 0

2 years ago

What is he empirical formula for the compound that is of 1.85 moles of nitrogen and 4.63 miles of oxygen

BartSMP [9]

The empirical formula is N₂O₅.

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles, so our job is to calculate the molar ratio of N:O.

I like to summarize the calculations in a table.

Element Moles Ratio¹ ×2² Integers³

N 1.85 1 2 2

O 4.63 2.503 5.005 5

¹To get the molar ratio, you divide each number of moles by the smallest number (1.85).

²Multiply these values by a number (2) that makes the numbers in the ratio close to integers.

³Round off the number in the ratio to integers (2 and 5).

The empirical formula is N₂O₅.

4 0

2 years ago