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kakasveta [241]
3 years ago
8

Both astrology and astronomy study the stars the major difference is A astronomy is a science that uses the scientific method B

astrology is a science that uses the scientific method C astronomy is based on opinions and beliefs D astrology is based on opinions and beliefs
Chemistry
1 answer:
SOVA2 [1]3 years ago
4 0
The major difference is A, because astrology is a pseudoscience, and that sets it apart from astronomy more than D.
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___________________is the rate that an object moves in a certain direction. Question 3 options:
Nesterboy [21]

Answer: Velocity

Explanation:

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3 years ago
Nitric acid can be produced by the reaction of gaseous nitrogen dioxide with water. 3 no2(g) + h2o(ℓ) −→ 2 hno3(ℓ) + no(g) if 85
Naya [18.7K]
The balanced equation for the above reaction is as follows;
3NO₂ + H₂O --> 2HNO₃ + NO
stoichiometry of NO₂ to NO is 3:1
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
volume of gas is directly proportional to number of moles of gas.
therefore stoichiometry can be applied for volume as well.
volume ratio of NO₂ to NO is 3:1
volume of NO₂ reacted - 854 L
therefore volume of NO formed - 854 L /3 = 285 L
volume of NO formed - 285 L
8 0
3 years ago
Daniel is conducting an experiment on magnetic objects. He completes more than one trial. Why is it important for Daniel to do t
Luba_88 [7]

Answer:The conclusion is less accurate.

Explanation:

Feb 17, 2021 — He completes more than one trial. Why is it important for Daniel to do this?

4 0
2 years ago
Which source should be avoided when conducting scientific research? encyclopedias
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Wikipedia
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3 0
3 years ago
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An unknown compound contains 38.7 % calcium, 19.9 % phosphorus and 41.2 % oxygen. what is the empirical formula of this compound
Temka [501]

The amount per 100 g is:

38.7 % calcium = 38.7g Ca / 100g compound = 38.7g

19.9 % phosphorus = 19.9g P / 100g compound = 19.9g

41.2 % oxygen = 41.2g O / 100g compound = 41.2g

The molar amounts of calcium, phosphorus and oxygen in 100g sample are calculated by dividing each element’s mass by its molar mass:

Ca = 38.7/40.078 = 0.96

P = 19.9/30.97 = 0.64

O = 41.2/15.99 = 2.57

C0efficients for the tentative empirical formula are derived by dividing each molar amount by the lesser value that is 0.64 and in this case, after that multiply wih 2.

Ca = 0.96 / 0.64 = 1.5=1.5 x 2 = 3

P = 0.64 / 0.64 = 1 = 1x2= 2

O = 2.57 / 0.64 = 4= 4x2= 8

Since, the resulting ratio is calcium 3, phosphorus 2 and oxygen 8

<span>So, the empirical formula of the compound is Ca</span>₃(PO₄)₂

5 0
3 years ago
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