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DENIUS [597]
2 years ago
7

A higher than normal high tide is called

Chemistry
1 answer:
alina1380 [7]2 years ago
8 0
It is called a spring tide
You might be interested in
How many moles in 2 h2o molecules
alexandr1967 [171]

Answer:

2 molecules of water represents 3.32 x 10^-24 moles of water.

Explanation:

To find the solution to this problem, you have to use the concept of Avogadro´s number, that is in 1 mol of any element o compound there are                    6.022 x 10^23 molecules. Then,

1 mol H2O ------------- 6.022 x 10^23 molecules

x= 3.32 x 10^-24 ---- 2 molecules.

2 molecules of water represents 3.32 x 10^-24 moles of water.

5 0
2 years ago
問上面照片的題目,何者不是構成蛋白質的主要成分原素?
maxonik [38]
What does this even say
8 0
3 years ago
If objects at the same distance suddenly decreased in mass the gravitational force between them would
Flauer [41]

Answer:

Gravitational force is also decreases.

Explanation:

Gravitational force is directly proportional to the mass of an object and inversely properly to the distance between their centres. Directly means if one increases the other automatically increases or if one decreases, the other also decreases. There is a direct relationship between mass and gravitational force so if mass of the bodies decrease, the gravitational force is also decreases.

7 0
3 years ago
What is the pH of a 0.028M solution (pH= -log(M))<br><br> A) 3.56<br> B) 2.88<br> C) 1.55<br> D) 1
kupik [55]

Answer:

1.55

Explanation:

-log(M)=pH

- Hope that helps! Please let me know if you need further explanation.

4 0
3 years ago
If 175mL of oxygen is produced at STP, how many grams of hydrogen peroxide, H2O2
Vlad [161]

Answer:

0.53g

Explanation:

We'll begin by converting 175mL to L. This is illustrated below:

1000mL = 1L

Therefore 175mL = 175/1000 = 0.175L

Next, we shall calculate the number of mole of O2 that occupy 0.175L. This is illustrated below:

1 mole of O2 occupy 22.4L at stp.

Therefore, Xmol of O2 will occupy 0.175L i.e

Xmol of O2 = 0.175/22.4

Xmol of O2 = 7.81×10¯³ mole

Therefore, 7.81×10¯³ mole of O2 occupy 175mL.

Next, we shall determine the number of mole of H2O2 that decomposed to produce 7.81×10¯³ mole of O2. This is illustrated below:

2H2O2 —> 2H2O + O2

From the balanced equation above,

2 moles of H2O2 decomposed to produce 1 mole of O2.

Therefore, Xmol of H2O2 will decompose to produce 7.81×10¯³ mole of O2 i.e

Xmol of H2O2 = 2 x 7.81×10¯³

Xmol of H2O2 = 1.562×10¯² mole

Therefore, 1.562×10¯² mole of H2O2 decomposed in the reaction.

Finally, we shall convert 1.562×10¯² mole of H2O2 to grams. This is illustrated below:

Molar mass of H2O2 = (2x1) + (16x2) = 34g/mol

Mole of H2O2 = 1.562×10¯² mole

Mass of H2O2 =..?

Mole = mass /Molar mass

1.562×10¯² = mass /34

Cross multiply

Mass of H2O2 = 1.562×10¯² x 34

Mass of H2O2 = 0.53g

Therefore, 0.53g of Hydrogen peroxide, H2O2 were decomposition in the reaction.

3 0
3 years ago
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