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lisabon 2012 [21]
3 years ago
9

What is the activation energy of this reaction? 50 kJ 100 kJ 150 kJ 200 kJ

Chemistry
2 answers:
iogann1982 [59]3 years ago
7 0

Answer:

50kj

Explanation:

Just took the test

hammer [34]3 years ago
6 0

Answer:

50 kJ

Explanation:

Activation energy is between the energy of reactants and the peak of the curve.

200 kJ - 150 kJ = 50 kJ

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Imagine that you helped to discover a new element; A=302;Z=119. How many protons, electrons, and neutrons are in each atom it th
oee [108]

Explanation:

Given that,

Mass number, A = 302

Atomic number, Z = 119

We know that, atomic number = no of protons

Protons = 119

Mass no. = No. of neutrons + No. of protons

302 = No. of neutrons + 119

No. of neutrons = 302 - 119

= 183

No. of electrons = No. of protons

= 119

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3 years ago
What charge is there on a lithium ion?
gogolik [260]
Lithium is in the Alkali Metal group or 1A column. The atoms in this group form ions with a 1+ charge. Lithium ion’s charge is 1+.
3 0
3 years ago
Read 2 more answers
A 100 g sample of potassium chlorate, KCIO3(s), is completely decomposed by heating:
Mama L [17]
Explanation:
In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for pressure and temperature.
Since no mention of those conditions was made, I'll assume that the reaction takes place at STP, Standard Temperature and Pressure.
STP conditions are defined as a pressure of
100 kPa
and a temperature of
0
∘
C
. Under these conditions for pressure and temperature, one mole of any ideal gas occupies
22.7 L
- this is known as the molar volume of a gas at STP.
So, in order to find the volume of oxygen gas at STP, you need to know how many moles of oxygen are produced by this reaction.
The balanced chemical equation for this decomposition reaction looks like this
2
KClO
3(s]
heat
×
−−−→
2
KCl
(s]
+
3
O
2(g]
↑
⏐
⏐
Notice that you have a
2
:
3
mole ratio between potassium chlorate and oxygen gas.
This tells you that the reaction will always produce
3
2
times more moles of oxygen gas than the number of moles of potassium chlorate that underwent decomposition.
Use potassium chlorate's molar mass to determine how many moles you have in that
231-g
sample
231
g
⋅
1 mole KClO
3
122.55
g
=
1.885 moles KClO
3
Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate
1.885
moles KClO
3
⋅
3
moles O
2
2
moles KClO
3
=
2.8275 moles O
2
So, what volume would this many moles occupy at STP?
2.8275
moles
⋅
22.7 L
1
mol
=
64.2 L
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3 years ago
What type of property is mass
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Answer:

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4 years ago
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Bond [772]

Answer:

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