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lisabon 2012 [21]
2 years ago
9

What is the activation energy of this reaction? 50 kJ 100 kJ 150 kJ 200 kJ

Chemistry
2 answers:
iogann1982 [59]2 years ago
7 0

Answer:

50kj

Explanation:

Just took the test

hammer [34]2 years ago
6 0

Answer:

50 kJ

Explanation:

Activation energy is between the energy of reactants and the peak of the curve.

200 kJ - 150 kJ = 50 kJ

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Consider the chemical reaction: 2 cu(no3)2→ 2 cuo (s) + 4 no2 (g) + o2 (g)when 9.378 g of cu(no3)2 completely decomposed, how
Allushta [10]

2Cu(NO3)2 ---------->    2CuO (s) +4NO2 (g) + O2(g)

9.378g=0.05moles   

no of moles = weight / MW = 9.378/187.56 = 0.05moles

as per the above reaaction 2moles of Cu(NO3)2 can produce 4moles of N2

                                                    0.05moles Cu(NO3)2 can produce (0.05*4)/2 = 0.1moles of N2

and 2moles of Cu(NO3)2 can produce 1moles of O2

       0.05moles Cu(NO3)2 can produce (0.05*1)/2 = 0.025moles of O2

Total moles of gas i.e., N2 and O2 =0.1+0.025 = 0.125moles

From PV = nRT

       V = nRT/ P = 0.125*0.0821*273 = 2.80166Lit option is correct

6 0
3 years ago
Chose one that best fits the question
kramer

Answer:

Explanation:

The fourth one.

6 0
3 years ago
Read 2 more answers
Which of the following is a substance that is found between the cell membrane and the nuclear us which primarily consist of wate
Kazeer [188]
<span>Cytoplasm is the substance between the cell membrane and the nucleus which primarily consists of water and holds organelles.</span><span>
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3 0
3 years ago
The heat of vaporization of 1–pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K•mol. What is the approximate b
tensa zangetsu [6.8K]

Answer:

375 K

Explanation:

Using the experssion shown below as:

\Delta G^0=\Delta H^0_{vap}-T\Delta S^0_{vap}

At vaporization point, the liquid and the gaseous phase is in the equilibrium.

Thus,

\Delta G^0=0

So,

Delta H^0_{vap}=T\Delta S^0_{vap}

Given that:

Delta H^0_{vap}=55.5\ kJ/mol

Also, 1 kJ = 10³ J

So,

Delta H^0_{vap}=55500\ J/mol

\Delta S^0_{vap}=148\ J/K.mol

So, temperature is :

T=\frac{Delta H^0_{vap}}{\Delta S^0_{vap}}

T=\frac{55500}{148}

<u>T= 375 K</u>

3 0
3 years ago
Selected properties of antimony (Sb) and iodine (I) are listed in the table below. Element Atomic radius (pm) First ionization e
Effectus [21]

Let us check each statement one by one

a) Sb has a lower ionization energy but a higher electronegativity than I. : As per values given : Definitely Sb has lower ionization energy however the electronegativity of Sb is lower than that of iodine

b) Sb has a higher ionization energy but a lower electronegativity than I. FAlse:

Sb has lower ionization energy than I

c) Sb has a lower ionization energy and a lower electronegativity than I. True

d) Sb has a higher ionization energy and a higher electronegativity than I. False


4 0
4 years ago
Read 2 more answers
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