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Ostrovityanka [42]
3 years ago
15

Man A (70kg) and Man B (90kg) are hanging motionless from a platform at rest. What is the tension TA in the top rope if the plat

form accelerates upward at a constant rate of 2 m/s2
Physics
1 answer:
Damm [24]3 years ago
3 0

Answer:

The tension in the upper rope (top rope), T1 = 1,888 N

Explanation:

The Parameters that were given:

Mass A, M1 = 70kg

Mass B. M2 = 90kg

acceleration, a = 2 m/s2

Assume the rope doesn't have mass, acceleration due to gravity, g

= 9.8 m/s2

The tension, T in a platform = m (a + g)

Then the tension, T1 in the upper rope = m1 (a + g) + T2

Where T2 = Tension in the lower rope

First, we calculate T2

Since the platform accelerates upward the acceleration would be positive

T2 =  m2 (a + g)

T2 = 90kg ( 2 m/s2 + 9.8 m/s2)

T2 = 1,062N

To calculate the tension T1,

T1 = m1 (a + g) + T2

= 70kg (2 m/s2 + 9.8 m/s2) + 1062N

T1 = 1,888 N

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The density of the block is mathematically given as

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Question Parameters:

50 cm by 100 cm by 200 cm has a mass of 8000 g.

Generally the equation for the density  is mathematically given as

phi=\frac{m}{v}

Where

v= 50 cm * 100 cm * 200 cm

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phi=8e-4

For more information on density

brainly.com/question/14010194

7 0
3 years ago
The eiffel tower is a steel structure whose height increases by 19.5 cm when the temperature changes from −8 to +42 °c. what is
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 The coefficient of expansion is 13 * 10^-6 m per meter length.per oK 
The temperature difference = 42 - - 8 = 50 oC 
delta T = (42 + 273) - (-8 + 273) = 50 oK 
delta L = L * 13* 10^6 m/oK 
oK = 50 oK delta L = 19.5 cm = 19.5 cm [1m / 100 cm] = 0.195m 
So we need to find the length and it is computed by:
0.195= L * 13 * 10^-6 * 50 L = 0.195 / (13*10^-6*50) L = 300 m 
6 0
3 years ago
A spring has a spring constant of 30000 N/m. How far must it be stretched (in meters) for its potential energy to be 47 J?
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The elastic potential energy in a spring is given by:
EPE = 1/2 kx²
x = √(2 x 47 / 30,000)
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5 0
4 years ago
A ski gondola is connected to the top of a hill by a steel cable oflength 620 m and diameter 1.5 cm. As thegondola comes to the
klemol [59]

Answer:

Explanation:

Given

Length of cable L=620 m

Diameter of cable d=1.5 cm

time taken to return to original position T=14 s

time taken to cover distance L

t=\frac{T}{2}=7 s

velocity

v=\frac{L}{t}=\frac{620}{7}=88.57 m/s

(b)Relation between velocity of wave Tension is

v=\sqrt{\frac{T}{\mu }} , where \mu =mass per unit Length

T=v^2\cdot \mu

T=(88.57)^2\cdot \frac{m}{L}

T=(88.57)^2\cdot \frac{\rho AL}{L}

where \rho =density\ of\ steel =7850 kg/m^3

A=area\ of\ cross-section=\frac{\pi }{4}d^2=1.76\times 10^{-4} cm^2

T=(88.57)^2\cdot 7850\times 1.76\times 10^{-4}

T=10,883 N

5 0
3 years ago
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ExtremeBDS [4]
What a sloppy question ! The purpose of a fuse or circuit breaker is to shut down the circuit when current reaches a magnitude indicating danger due to a serious malfunction. When current IS flowing in the circuit, it's always flowing at the same speed.
3 0
3 years ago
Read 2 more answers
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