Walking at a speed of 2.1 m/s, in the first 2 s John would have walked
(2.1 m/s) (2 s) = 4.2 m
Take this point in time to be the starting point. Then John's distance from the starting line at time <em>t</em> after the first 2 s is
<em>J(t)</em> = 4.2 m + (2.1 m/s) <em>t</em>
while Ryan's position is
<em>R(t)</em> = 100 m - (1.8 m/s) <em>t</em>
where Ryan's velocity is negative because he is moving in the opposite direction.
(b) Solve for the time when they meet. This happens when <em>J(t)</em> = <em>R(t)</em> :
4.2 m + (2.1 m/s) <em>t</em> = 100 m - (1.8 m/s) <em>t</em>
(2.1 m/s) <em>t</em> + (1.8 m/s) <em>t</em> = 100 m - 4.2 m
(3.9 m/s) <em>t</em> = 95.8 m
<em>t</em> = (95.8 m) / (3.9 m/s) ≈ 24.6 s
(a) Evaluate either <em>J(t)</em> or <em>R(t)</em> at the time from part (b).
<em>J</em> (24.6 s) = 4.2 m + (2.1 m/s) (24.6 s) ≈ 55.8 m
Answer:
V = E*d
D = 1.5 cm * [1 m / 100 cm] = 0.015m
V = 2.9^10^6 N/C * 0.015 m
V = 1.93 * 10^9 V
The units don't agree in any simple way, but the formula is correct, and it does work.
Explanation:
Answer: Accelaration is 2.77 m/s*s
<h2 />
Explanation:
V0=0km/h=0m/s
V1=100 km/h=27.7 m/s
t=10s=
Use equation for accelaration : a=(V1-V0)/t
a=(0m/s-27.7m/s)/10s
a=-27.7s/10s
a=2.77m/s*s
Answer:
Korean War: 25 June 1950 – 27 July 1953
Many then believed that the conflict was likely to soon escalate into a full-scale war between the three countries, the US, the USSR, and China. CBS war correspondent Bill Downs wrote in 1951 that, "To my mind, the answer is: Yes, Korea is the beginning of World War III.
Explanation:
Answer:
A) 
Explanation:
Maximum voltage =
Maximum voltage and rms voltage are related to each other by
