All categories

3 years ago

Which nervous system includes the spinal cord

Physics

2 answers:

Alex787 [66]3 years ago

6 0

Answer: C. central

Explanation:

Deffense [45]3 years ago

5 0

Answer:

the central nervous system

You might be interested in

In a circuit, three pieces of wire labeled A, B and C are joined at a common point, D. If wire B carries 1.5 mA in a direction a

Alex_Xolod [135]

Answer:

correct option is a. 0.2 mA toward D

Explanation:

given data

B carries = 1.5 mA

C carries current = 1.3 mA

solution

we take positive direction of current going away from the point D

and negative direction of current coming towards point D

so we use here kirchoff's current law that is

iA + iB + iC = 0 ......................1

iA + 1.5 + (-1.3) = 0

iA = - 0.2 mA

so that current in wire A is 0.2 mA towards point D

correct option is a. 0.2 mA toward D

7 0

3 years ago

How would a person who believes in the geocentric solar

Gemiola [76]

Id say A because the geocentric model is where the earth is at the center of the universe and all other planets, suns, stars, and moons are revolving around it

4 0

3 years ago

What organ provides support for our

Marina86 [1]

Answer:

Skin

Explanation:

6 0

3 years ago

7. A double-slit experiment uses coherent light of wavelength 633 nm with a slit separation of 0.100 mm and a screen placed 2.0

Illusion [34]

Answer:

The distance between first-order and second-order bright fringes is 12.66mm.

Explanation:

The physicist Thomas Young establishes through its double slit experiment a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

$\Lambda x = L\frac{\lambda}{d}$ (1)

Where $\Lambda x$ is the distance between two adjacent maxima, L is the distance of the screen from the slits, $\lambda$ is the wavelength and d is the separation between the slits.

The values for this particular case are:

$L = 2.0m$

$\lambda = 633nm$

$d = 0.100mm$

Notice that is necessary to express L and $\lambda$ in units of milimeters.

$L = 2.0m \cdot \frac{1000mm}{1m}$ ⇒ $2000mm$

$\lambda = 633nm \cdot \frac{1mm}{1x10^{6}nm}$ ⇒ $6.33x10^{-4}mm$

Finally, equation 1 can be used:

$\Lambda x = (2000mm)\frac{(6.33x10^{-4}mm)}{(0.100mm)}$

$\Lambda x = 12.66mm$

Hence, the distance between first-order and second-order bright fringes is 12.66mm.

8 0

3 years ago

Abigail runs one complete lap (400m) around the track, while Gabi runs a 50 meter dash in a straight line. Which runner had a gr

Ipatiy [6.2K]

Answer:

$\boxed {\boxed {\sf Gabi \ had \ greater \ displacement}}$

Explanation:

Displacement is the change in the position of an object.

Abigail runs a complete lap around the track, which is 400 meters. Even though she ran 400 meters, she has no displacement. If she starts and ends at the same spot, there is no change in position.

Gabi runs a 50 meter dash in a straight line. Gabi has 50 meters of displacement. She runs in a straight line and is 50 meters away from where she began.

While Abigail ran the farther distance, Gabi had the greater displacement.

4 0

3 years ago

Read 2 more answers