All categories

2 years ago

What percent of 51 is 65?

Mathematics

1 answer:

Mila [183]2 years ago

6 0

Answer:127.45

Step-by-step explanation:

Percentage solution with steps:

Step 1: We make the assumption that 51 is 100% since it is our output value.

Step 2: We next represent the value we seek with x.

Step 3: From step 1, it follows that $100\%=51$.

Step 4: In the same vein, $x\%=65$.

Step 5: This gives us a pair of simple equations:

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

Step 7: Taking the inverse (or reciprocal) of both sides yields

Therfore: 51% of 65 is 127.45

You might be interested in

I need this answer ?

FromTheMoon [43]

Are you sure you need help with that easy problem read it slowly then ask

7 0

3 years ago

Can someone solve what is n/n^3

emmasim [6.3K]

Answer:

Alex = No B.

Step-by-step explanation:

1) Use Quotient Rule: $\frac{x^{a} }{x^{b} } =x^{a-b}$

$n^{1-3}$

2) Simplify 1 - 3 = 2

$n^{-2}$

3) Use Negative Power Rule: $x^{-a} =\frac{1}{x^{a} }$

$\frac{1}{n^{2} }$

3 0

2 years ago

The table shows the total profits earned from magazine sales.

coldgirl [10]

Answer:

C. y= 14x+20

Step-by-step explanation:

By looking at the table, you can put in the x-values into all of the equations until you find the corresponding y-values that matches with the values in the table. For example: y= 14(2)+ 20, y=48. y= 14(20) +20, y=300. Hope this helped!

8 0

3 years ago

Read 2 more answers

Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60

anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

$L=5W-60$ (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

$Area=W*L=W*(5W-60)$ (Equation #2)

Since the Area of the yard is $800 ft^2$ , then equation #2 turns into:

$800=W*(5W-60)$

Now, we rearrange this equation:

$800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0$

We can divide the equation by 5 :

$W^2-12W-160=0$

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since $(-20)*8=160$ and $-20+8=-12$ . The equation factorised looks like this:

$(W-20)(W+8)=0$

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

$5*20-60=40$

Therefore, the dimensions of the yard are W=20ft and L=40ft.

7 0

3 years ago

A lemonade recipe calls for LaTeX: \frac{1}{4}1 4 cup of lemon juice for every cup of water.

Delvig [45]

Can you explain more

pls

4 0

3 years ago