Answer:
h≅ 58 m
Explanation:
GIVEN:
mass of rocket M= 62,000 kg
fuel consumption rate = 150 kg/s
velocity of exhaust gases v= 6000 m/s
Now thrust = rate of fuel consumption×velocity of exhaust gases
=6000 × 150 = 900000 N
now to need calculate time t = amount of fuel consumed÷ rate
= 744/150= 4.96 sec
applying newton's law
M×a= thrust - Mg
62000 a=900000- 62000×9.8
acceleration a= 4.71 m/s^2
its height after 744 kg of its total fuel load has been consumed
h= 58.012 m
h≅ 58 m
Answer:
(a) 2.3 x 10^-12 N
(b) 1.6 x 10^5 m/s
Explanation:
q1 = 1.6 x 10^-19 C
q2 = 1.6 x 10^-19 C
r = 1 x 10^-8 m
(a) the electrostatic force is given by
F = K q1 x q2 / r^2
F = ( 9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (1 x 10-^-8)^2
F = 2.3 x 10^-12 N
The force is attractive in nature because the nature of charge on electron and proton s opposite to each other.
(b) The electrostatic force is balanced by the centripetal force actig on the electron.
F = mv^2 / r
where, r be the radius of orbit and v be the velocity of electron in the orbit.
2.3 x 10^-12 = (9.1 x 10^-31 x v^2) / (1 x 10^-8)
v = 1.6 x 10^5 m/s
Answer:
2 True
Explanation: The arrows on a motion map should point in the direction of motion.
