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igor_vitrenko [27]
3 years ago
15

Radiant energy comes from the _______.

Physics
2 answers:
g100num [7]3 years ago
8 0
Radiant energy comes from the sun.
C. Sun
snow_lady [41]3 years ago
7 0

Answer:

C. Sun

Explanation:

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Heat required = mass× latent heat Q = 0.15 × 871 ×

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Which vector below goes from (0,0) to (1,-3)?
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I think D. It starts at (0.0) and goes to the correct points so it makes sense

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An example of kinetic energy is a _____.
zhenek [66]

Answer:

An example of kinetic energy is a <u><em>car coming to a stop</em></u>

Explanation:

Kinetic energy is the energy that a body or system possesses due to its movement. In physics this energy is defined as the amount of work necessary to accelerate a body of a certain mass and in rest position, until reaching a certain speed. This energy obtained will remain unchanged as long as this body does not vary its speed. That is, kinetic energy measures how many changes an object that is moving can cause.

<u><em>An example of kinetic energy is a car coming to a stop</em></u>. If the car is moving and comes to a stop, there is a change in speed, therefore in movement, eventually producing a change in kinetic energy. This energy depends on the mass of the body, in this case the car, and the speed.  As the speed decreases, the kinetic energy will decrease.

4 0
4 years ago
Practice
stiv31 [10]

Answer:

The answer is Letter B The car travel at a constant veloc

5 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
4 years ago
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