Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
It's D.
Step-by-step explanation:
Convert each number to decimal format.
It is option D , if we convert as above we get
7.36799, 7.36666.., 7.363636.., 7.33333..
250cm^2
To find the area of shape B we need to find the factor by which you multiply to get from 12 to 15. To find this we divide 15 by 12 to get 1.25. We now multiply the area of shape A (200) by the factor 1.25 to get the answer. The answer is 250cm^2.
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Answer: 6
Step-by-step explanation: set the equations equal to each other then solve. plug that number into the equation for AB
1 meter = 100 centimeters, so 120 centimeters equal to 1.2 meters.
