All categories

3 years ago

Answer Three of these question and you will be the brainliest. Answer this with solution please

Mathematics

2 answers:

Annette [7]3 years ago

7 0

Answer: 1) Option A

2) Option A

3) Option C

Step-by-step explanation: 1) Option A, because 0 is greater than -4, and it is not true that -4 is greater than 0.

2) Option A

3) Option C, -3°F

11Alexandr11 [23.1K]3 years ago

5 0

Answer:

1. 0<-4

2. |-2|, 3, |-5|, 7, |-9|

3. -3

You might be interested in

A girl starts to walk to her school, which is 20 miles away, at 6:50 and at a rate of 3 miles per hour. After a while, her dad p

Alinara [238K]

The girl walked 5 miles.

4 0

3 years ago

Read 2 more answers

Find th area of the circle. Use 3.14 for π round to the nearest unit.

kramer

I think the answer is C because you would A=Pi x r x 2

4 0

3 years ago

Read 2 more answers

Please this is my last question help me

sladkih [1.3K]

Hopes this helps: i used a visual as well

3 0

3 years ago

The price of a watch was increased by 20% to £144. What was the price before the increase?

hammer [34]

Answer:

120 pounds

Step-by-step explanation:

Since the new cost is 144 pounds and this is 20% more, this is 120% of the original price. Remember 100+20 = 120. To find the original price set up a proportion with these values:

$\frac{144}{x}=\frac{120}{100}$

Solve for the original price by cross multiplying numerator with denominator.

x(120) = 144(100)

120x = 14400

x= 120 pounds

6 0

3 years ago

What is the equation of this graphed line?

barxatty [35]

Answer:

$y=-\frac{1}{3}x-5$

Step-by-step explanation:

Given:

The two points on the line are:

$(x_1,y_1)=(-6,-3)\\(x_2,y_2)=(6,-7)$

Now, for a line with two points on it, the slope of the line is given as:

$m=\frac{y_2-y_1}{x_2-x_1}$

For the points $(x_1,y_1)=(-6,-3)\ and\ (x_2,y_2)=(6,-7)$ , slope is:

$m=\frac{-7-(-3)}{6-(-6)}\\m=\frac{-7+3}{6+6}\\m=\frac{-4}{12}=-\frac{1}{3}$

Now, for a line with slope 'm' and a point $(x_1,y_1)$ on it is given as:

$y-y_1=m(x-x_1)$

Plug in all the values and determine the equation of the line. This gives,

$y-(-3)=-\frac{1}{3}(x-(-6))\\\\y+3=-\frac{1}{3}(x+6)\\\\y+3=-\frac{1}{3}x-\frac{1}{3}\times 6\\\\y+3=-\frac{1}{3}x-2\\\\y=-\frac{1}{3}x-2-3\\\\y=-\frac{1}{3}x-5$

Therefore, the equation of the line is:

$y=-\frac{1}{3}x-5$

4 0

3 years ago