Altitude is shown
Hope this helps :)
Answer:
12.36%
Step-by-step explanation:
For year 1:
T(1) = 1000(1.06)¹
T(1) = 1060
After two years, t = 3
T(3) = 1000(1.06)³
T(3) = 1191.06
The percent of the increase is
[(T(3) - T(2)/T(2)]*100%
[(1191.06 - 1060)/1060]*100%
12.36%
Answer:
the mean and the standard deviation is 0.92 and 0.01808 respectively
Step-by-step explanation:
The computation of the mean and the standard deviation is shown below:
The mean is 0.92
And, the standard deviation is
= √0.92 × (1 - 0.92) ÷ √225
= √0.92 × 0.08 ÷ √225
= √0.0736 ÷ √225
= √3.27
= 0.01808
Hence, the mean and the standard deviation is 0.92 and 0.01808 respectively
If you're meaning write it in standard form it would be
y=1/4x+1