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2 years ago

9

Help with homework please

1 answer:

BabaBlast [244]2 years ago

6 0

Answer:

1

Step-by-step explanation:

Start at -0.5 and go toward 0.5.

From -0.5 to zero, it's a distance of 0.5.

From zero to 0.5, it's also a distance of 0.5.

Add the two distances, 0.5 + 0.5 = 1.

The distance between -0.5 to 0.5 is 1.

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2 years ago

How do i factor this trinomial 5y^2 — 7y — 6

scZoUnD [109]

Answer:

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2 years ago

Can u help me wit the answer?? Plz???

Vanyuwa [196]

Average weight is when you add up all the weight and divide by the number of objects

if you count the number of x's you will see that you have 10 sandwiches
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7 0

2 years ago

100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!

Volgvan

Using weighed averages, it is found that:

The final grade is 91.
The final grade is 66.8.
The higher grade would be 79.55, with the second grading scheme.
On average, she sold $48,280 per day.
On average, she makes $12.5 per hour.

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To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

Grade of 91, with a weight of 67%.
Grade of 91, with a weight of 33%.

Thus:

$F = 91\times0.67 + 91\times0.33 = 91$

The final grade is 91.

---------------------------------------

Question 2:

Grade of 83, with a weight of 40%(highest grade).
Grade of 60, with a weight of 30%.
Grade of 52, with a weight of 30%.

Thus:

$F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8$

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

75 with a weight of 25%.
80 with a weight of 10%.
85 with a weight of 40%.
62 with a grade of 25%.

Thus:

$F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25$

---------------------------------------

With teacher 2:

75 with a weight of 15%.
80 with a weight of 10%.
85 with a weight of 60%.
62 with a weight of 15%.

Thus:

$F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55$

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

Average of $36,432, with a weight of $\frac{3}{3+10} = \frac{3}{13}$
Average of $51,834, with a weight of $\frac{10}{13}$

Thus:

$A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280$

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

Average of $14.84, with a weight of $\frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}$
Average of $10.76, with a weight of $\frac{4}{7}$

Thus:

$A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5$

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

5 0

2 years ago

Please help me before it's to late I

gregori [183]

It’s 7.406 , that’s the correct answer

5 0

1 year ago