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Shtirlitz [24]
3 years ago
9

Help with homework please

Mathematics
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:

1

Step-by-step explanation:

Start at -0.5 and go toward 0.5.

From -0.5 to zero, it's a distance of 0.5.

From zero to 0.5, it's also a distance of 0.5.

Add the two distances, 0.5 + 0.5 = 1.

The distance between -0.5 to 0.5 is 1.

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C=40 bahshshahajehsh
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A garden is a rectangle 100 feet long and 50 feet wide. The portion of the garden devoted to herbs is 10 feet by 10 feet. The re
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Read 2 more answers
Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
2 years ago
Need Help with #5<br> 4 pts
olga_2 [115]
Answer = 10=21


When you’re multiplying numbers with exponents with the same base (10 is the base) all you have to do is add the exponents

18 and 3 are the exponents we’re dealing with, so we add them and get 21. The base stays the same

10^18 x 10^3 = 10^21

Answer = 10=21
8 0
3 years ago
Heba ate 1/12 of a box of cereal. Now the box is 3/4 full.
Alex Ar [27]
3/4 = 3/4*1

3/4 = 3/4 * 3/3 = 9/12

Box is 9/12 full after heba ate 1/12 of a box of cereal

Initial fraction will be 9/12+1/12

=10/12= 5/6
5 0
3 years ago
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