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bekas [8.4K]
4 years ago
15

If the pressure is initially 1.30 atm before the addition of the gas and the position of the piston does not change, what is the

new pressure inside of the cylinder?
Physics
1 answer:
Vladimir [108]4 years ago
4 0

Answer:

The new pressure inside of the cylinder is 2.6 atm.

Explanation:

Given that,

Initial pressure = 1.30 atm

If the number of moles is double after gas added.

The position of the piston does not change.

So, The volume will be same.

The pressure inside the cylinder before gas added

PV=nRT...(II)

After gas added,

P'V=nRT...(II)

We need to calculate the new pressure inside of the cylinder

Dividing equation (I) and (II)

\dfrac{PV}{P'V}=\dfrac{nRT}{n'RT}

\dfrac{P}{P'}=\dfrac{n}{n'}

Put the value into the formula

\dfrac{P}{P'}=\dfrac{n}{2n}

P'=2\times P

P'=2\times1.30

P'=2.6\ atm

Hence, The new pressure inside of the cylinder is 2.6 atm.

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