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2 years ago

The three types of seismic waves are P waves, S waves and T waves. Please select the best answer from the choices provided T F

Physics

2 answers:

ikadub [295]2 years ago

7 0

The correct answer is False

WINSTONCH [101]2 years ago

6 0

Answer:

FALSE

Explanation:

There exist only two types of seismic waves

1) P waves

2) S waves

P waves are compression waves which is produced due to pushing and pulling. These waves can travel trough any medium i.e. Solid, Liquid or Gas and also these waves travels at high speed.

S Waves are secondary waves which travels at slow speed comparative to P waves. These waves can only travel through solid rocks and travels at slower speed with respect to P waves

So given statement is not true.

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2 years ago

A car turns a certain curve of radius 24.98 m with constant linear speed of

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Answer:

3525.19 kg

Explanation:

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3 years ago

Why are hypothesis valuable even if it is not supported by data.

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3 years ago

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The circuit shown in the figure (Figure 1) uses a neon-filled tube. This neon lamp has a threshold voltage V0 for conduction, be

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Part 1)

Answer:

Explanation:

As we know by equation of charging of the capacitor we will have

$V = E(1 - e^{-t/RC})$

so we will have

$87 = 105(1 - e^{-t/RC})$

here we know that

$R = 3.00 \times 10^6 ohm$

$C = 0.250 \mu F$

so we have

$t = 1.32 s$

Part b)

Answer:

The time will increase.

Explanation:

As we know that on increasing the value of the resistance the the product of the resistance and capacitance will increase so the time will increase to get the above voltage.

Part c)

Answer:

The capacitor discharges through a very low resistance (the lamp filled with ionized gas), and so the discharge time constant is very short. Thus the flash is very brief.

Explanation:

Since the lamp resistance is very small so the energy across the lamp will totally lost in very short interval of time

Part d)

Answer:

Once the lamp has flashed, the stored energy in the capacitor is gone, and there is no source of charge to maintain the lamp current. The lamp "goes out", the lamp resistance increases, and the capacitor starts to recharge. It charges again and the process will repeat.

Explanation:

Since we know that the battery is connected to the given system so after whole energy of capacitor is flashed out it is again charged by the battery and the process will continue

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3 years ago