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valina [46]
1 year ago
14

The number of ways in which 4 squares can be chosen at random on a chess board such that they lie on a diagonal line?.

Mathematics
1 answer:
wariber [46]1 year ago
5 0

The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

<h3>What are permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

It is given that:

On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:

The required number of ways:

= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))

= 2[2[ 1 + 5 + 15+35] + 70]

= 364

Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ4

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3 letters without replacement 4 letters A B C D how many ways can this be done if the order of the choices matters
Veseljchak [2.6K]

Answer:

Since the order of choice matters, we will permute the values.                       a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

___  ___ ___

Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

So:

_<u>4</u>_ ___ ___

**Keep in mind that the 4 is the possible number of values this slot can have**

Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with  3 more alphabets

we can put any one of the 3 alphabets in this second slot, Hence:

_<u>4</u>_ <u>_3_</u> ___

Now that 2 of the 4 alphabets have been used, we are left with only 2 alphabets, so there are only 2 possible alphabets for slot 3

Therefore:

_<u>4</u>_ _<u>3</u>_ _<u>2</u>_

Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

Total possible words = 4 * 3 * 2

Total possible words = 24

We could've used the formula for Permutation as well

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2 years ago
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PIT_PIT [208]
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8 0
2 years ago
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Mrs Harvey is making fresh raspberry punch. Each pitcher needs 1/2 cup of raspberries. If she makes three pitcher how many cups
Nastasia [14]

Answer:

1.5 cups of raspberries

Step-by-step explanation:

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2 years ago
What is the exact value of x? 5⋅21^5x=16
IRINA_888 [86]

Answer:

x=  16 /20420505

Step-by-step explanation:

Let's solve your equation step-by-step.

5(215)x=16

Step 1: Simplify both sides of the equation.

20420505x=16

Step 2: Divide both sides by 20420505.

20420505x /20420505  =  16 /20420505

x=  16 /20420505

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2 years ago
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27 ÷ (-2 + (-7))

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