The hydrogen atom is not actually electronegative enough to form bonds to xenon. were the xenon-hydrogen bond to exist, what wou
ld be the structure of xeh4? double-click any atom and type xe to change the label. draw the molecule by placing atoms on the grid and connecting them with bonds. show all lone pairs of electrons.
1 answer:
Answer : The structure of will be square-planar.
Explanation :
In the given molecule , 'Xe' is the central atom and 'H' is the terminal atom.
Xenon has 8 valence electrons and hydrogen has 1 valence electron. Therefore, the total number of valence electrons are 8 + 4(1) = 12 electrons.
The number of electrons used in Xe-H bonding = 8 electrons
The remaining electrons which are used as lone pair on central atom (Xe) = 12 - 8 = 4 electrons
There are 4 bonding pairs and 2 lone pairs of electrons, they will be arranged in the octahedral arrangement around the central atom with 2 lone pairs of electrons on central atom. The lone pairs are arranged linearly across the central atom. The resulting structure will be square-planar.
The structure of is shown below.
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Answer: The volume is 57.52 mL if the temperature if raised to 343K.
Explanation:
Given: = 27 mL,
= 161 K
= ?,
= 343 K
According to Charles law, at constant pressure the volume of an ideal gas is directly proportional to temperature.
Formula used is as follows.
Thus, we can conclude that volume is 57.52 mL if the temperature if raised to 343K.
Answer:
Explanation:
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In this case, since the enthalpy change for any process is computed by subtracting the enthalpy of the final state and the enthalpy of the initial state, for the given phase change, we subtract the enthalpy of the liquid (final state) and the enthalpy of the solid (initial state) considering this a melting process:
Which makes sense because this process absorbs energy.
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