Question

Reactant X contains 199.3 J of chemical energy. Reactant Y contains 272.3 J of chemical energy. Product W contains 41.9 J of chemical energy. If the reaction loses 111.6 J of chemical energy as it proceeds, how much chemical energy must product Z contain? 318.1 J 429.7 J 541.3 J 625.1 J

Answer 1

Answer:

318.1 J

Explanation:

The reaction given is:

X + Y → W + Z

The chemical energy of the reaction (ΔU), is the variation of the chemical energy, so is the chemical energy of the products (UW and UZ) less the chemical energy of the reactants (UX and UY).

If the reaction loses the chemical energy, it must be negative, and the chemical energy that a substance contains, is positive.

ΔU = (UW + UZ) - (UX + UY)

-111.6 = (41.9 + UZ) - (199.3 +272.3)

-111.6 = 41.9 + UZ - 471.6

- UZ = - 429.27 + 111.6

-UZ = - 318.1

UZ = 318.1 J

Answer 2

Answer : The correct option is, 318.1 J

Solution :

The given chemical reaction will be,

$X+Y\rightarrow W+Z+Energy$

In this reaction, X and Y are the reactants and W and Z are the products.

As we know that the energy remains conserved during the chemical reaction.

So,

Sum of energy of product = Sum of energy of reactant

$W+Z+Energy=X+Y\\\\41.9J+Z+111.6J=199.3J+272.3J\\\\Z=318.1J$

Therefore, the amount of chemical energy of product Z contain will be, 318.1 J