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Liula [17]
2 years ago
14

Reactant X contains 199.3 J of chemical energy. Reactant Y contains 272.3 J of chemical energy. Product W contains 41.9 J of che

mical energy. If the reaction loses 111.6 J of chemical energy as it proceeds, how much chemical energy must product Z contain? 318.1 J 429.7 J 541.3 J 625.1 J
Chemistry
2 answers:
andriy [413]2 years ago
6 0

Answer:

318.1 J

Explanation:

The reaction given is:

X + Y → W + Z

The chemical energy of the reaction (ΔU), is the variation of the chemical energy, so is the chemical energy of the products (UW and UZ) less the chemical energy of the reactants (UX and UY).

If the reaction loses the chemical energy, it must be negative, and the chemical energy that a substance contains, is positive.

ΔU = (UW + UZ) - (UX + UY)

-111.6 = (41.9 + UZ) - (199.3 +272.3)

-111.6 = 41.9 + UZ - 471.6

- UZ = - 429.27 + 111.6

-UZ = - 318.1

UZ = 318.1 J

telo118 [61]2 years ago
5 0

Answer : The correct option is, 318.1 J

Solution :

The given chemical reaction will be,

X+Y\rightarrow W+Z+Energy

In this reaction, X and Y are the reactants and W and Z are the products.

As we know that the energy remains conserved during the chemical reaction.

So,

Sum of energy of product = Sum of energy of reactant

W+Z+Energy=X+Y\\\\41.9J+Z+111.6J=199.3J+272.3J\\\\Z=318.1J

Therefore, the amount of chemical energy of product Z contain will be, 318.1 J

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30 treadmills to 36 elliptical machines
scoundrel [369]

Answer:

what? that's 66 total, 6 more elliptical machines, a 1 to 1.2 ratio

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7 0
2 years ago
Read 2 more answers
Consider the following reactions and their respective equilibrium constants: NO(g)+12Br2(g)⇌NOBr(g)Kp=5.3 2NO(g)⇌N2(g)+O2(g)Kp=2
maxonik [38]

Answer:

Equilibrium constant of the given reaction is 1.3\times 10^{-29}

Explanation:

NO+\frac{1}{2}Br_{2}\rightleftharpoons NOBr....(K_{p})_{1}=5.3

2NO\rightleftharpoons N_{2}+O_{2}....(K_{p})_{2}=2.1\times 10^{30}

The given reaction can be written as summation of the following reaction-

2NO+Br_{2}\rightleftharpoons 2NOBr

N_{2}+O_{2}\rightleftharpoons 2NO

......................................................................................

N_{2}+O_{2}+Br_{2}\rightleftharpoons 2NOBr

Equilibrium constant of this reaction is given as-

\frac{[NOBr]^{2}}{[N_{2}][O_{2}][Br_{2}]}

=(\frac{[NOBr]}{[NO][Br_{2}]^{\frac{1}{2}}})^{2}(\frac{[NO]^{2}}{[N_{2}][O_{2}]})

=\frac{(K_{p})_{1}^{2}}{(K_{p})_{2}}

=\frac{(5.3)^{2}}{2.1\times 10^{30}}=1.3\times 10^{-29}

7 0
2 years ago
Read 2 more answers
What is the difference between a pure solvent and a solution? Do they have the same physical properties?
pychu [463]

Answer:

The physical properties of a solution are different from those of the pure solvent. ... Colligative properties are those physical properties of solutions of nonvolatile solutes that depend only on the number of particles present in a given amount of solution, not on the nature of those particles.

5 0
2 years ago
What is the energy change if 84.0 g of calcium oxide (CaO) reacts with excess water in the following reaction?
pochemuha
   The energy change  if 84.0 g   of CaO  react  with  excess  water is  98KJ of heat is released.

calculation
heat  =  number of moles  x  delta H

delta H = - 65.2  Kj/mol

first find the number of  moles  of  CaO reacted

moles = mass/molar mass
the molar mass  of CaO =  40 +  16=  56 g/mol
mass = 84 g
moles therefore = 84 g/56 g/mol =1.5 moles

Heat is therefore =  1.5 moles  x -65.2 = - 97.8 Kj = -98 Kj

  since  sign is  negative  the   energy  is released 

6 0
3 years ago
Give explanations for the large drops in melting point from C to Si and from Ge to Sn.
____ [38]

As we move down the group, the metallic bond becomes more stable and the formation of forming covalent bond decreases down the group due to the large size of elements.

Covalent and metallic bonding leads to higher melting points. Due to a decrease in attractive forces from carbon to lead there is a drop in melting point.

Carbon forms large covalent molecules than silicon and hence has a higher melting point than silicon.

Similarly, Ge also forms a large number of covalent bonds and has a smaller size as compared to that of Sn. Hence melting point decreases from Ge to Sn.

The order will be C>Si>Ge>Pb>Sn.

To learn more about the covalent bond, visit: brainly.com/question/10777799

#SPJ4

3 0
1 year ago
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