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sasho [114]
3 years ago
9

The bonds S-S, O-H and Ca-Cl are, respectively, a) nonpolar covalent, polar covalent, ionic polar covalent, b)nonpolar covalent,

ionic ionic, polar covalent, c)nonpolar covalent, nonpolar covalent, ionic, ionic
Chemistry
1 answer:
Brums [2.3K]3 years ago
7 0

Answer:

nonpolar covalent, polar covalent, ionic

Explanation:

From the question ,

S - S Bond -

Both the atom are same , hence , making a non polar bond , because of no difference between the electronegativity of the atom ,

Hence , the S-S Bond is non polar covalent bond .

O-H bond -

The Oxygen atom is more electronegative than the hydrogen atom , so the bond is polar in nature .

And as the bond is formed by sharing ,

Therefore ,

O-H bond is polar covalent bond .

Ca-Cl bond -

Calcium is a metal , whereas , Chlorine is a non - metal , the bond is ionic in nature ,

Hence , Ca-Cl bond is  ionic  in nature .

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I agree with what you've chosen for question two and three.

I would choose C for the fourth question and argue that you shall also go with C for question five.

One of the main ideas about repetition is to have multiple <em>Trials</em>- or independent experiments-<em> </em>for a single independent variable using identical experimental setup. The table presented in option C is the only one among the four choices that allots spaces for measurements from multiple independent experiments.

Hypotheses are predictions of the outcome of a particular experiment. A hypothesis is <em>correct</em> only if it accurately describes the outcome of an experiment. The <em>hypothesis</em>, not the data, would have to be revised if the two doesn't fit. The researcher could keep developing and testing new hypotheses until arriving at a correct one.

Additionally, I would prefer option B over option D in the first question- responses to that question can depends on what your teacher says about the validity of different sources, given that <em>neither </em><em>B</em><em> nor </em><em>D</em><em> </em> are reliable as sources that one would like to cite in a paper.

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avanturin [10]

Answer:

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Explanation:

In order to calculate the weight of Fe₃O₄ in 100.0 g of Fe₂O₃ we need elements in common between both substances, for instance, the mass of Fe in each one. We will use the molar mass of Fe = 55.84g/mol The conversion factors we need are:

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Then, we can use proportions:

100.0gFe_{2}O_{3}.\frac{111.68gFe}{159.69gFe_{2}O_{3}} .\frac{231.54gFe_{3}O_{4}}{167.52gFe} =96.66gFe_{3}O_{4}

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