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kakasveta [241]
4 years ago
11

one atmospheric compound is responsible (after it have dissolved in water) for both the general acidity of normal rainwater and

the acidity of much soil. What is this compound?
Chemistry
1 answer:
ivolga24 [154]4 years ago
6 0

Carbon dioxide is the atmospheric compound that is responsible (after it have dissolved in water) for both the general acidity of normal rainwater and the acidity of much soil. Natural rain water is slightly acidic because carbon dioxide combined with water in the air forms carbonic acid, which is a weak acid.

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Which of these is a mixture??<br><br> A.) salad<br> B.) potassium<br> C.) water<br> D.) sugar
tensa zangetsu [6.8K]
Salad would be a mixture because it is not chemically combined, if needed you could physically take it apart. So your answer would be A.)
8 0
4 years ago
Read 2 more answers
How many milligrams of CO exist in 12000 liters of air with 10 ppm of CO?
VARVARA [1.3K]

Answer:

The mass of CO in 12,000 Liters of air is 12\times 10^4 mg.

Explanation:

The ppm is the amount of solute (in milligrams) present in one Liter of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

\text{ppm}=\frac{\text{Mass of solute}(mg)}{\text{Volume of solution}(L)}

The ppm concentration of CO = 10 ppm

Mass of CO = m

Volume of air = 12,000 L

10 =\frac{m}{12,000 L}

m=10\times 12,000 mg=120,000 mg=12\times 10^4 mg

The mass of CO in 12,000 Liters of air is 12\times 10^4 mg.

3 0
3 years ago
Can someone help me answer this homework problem. this is my homework.
sleet_krkn [62]

Answer:

12

Explanation:

The coefficient of the CO2 shows the amount of CO2 needed in the reaction so to react with 11 water, 12 molecules of carbon dioxide is needed.

8 0
3 years ago
Please help guys if you know it!
iogann1982 [59]
The second one is correct
4 0
3 years ago
Please help.
Fed [463]
<h2>Answer: O: 1s22s22p4</h2>

Explanation: In writing the electron configuration for oxygen the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for O go in the 2s orbital. The remaining four electrons will go in the 2p orbital. Therefore the O electron configuration will be 1s22s22p4.

8 0
3 years ago
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