You hear three beats per second when two sounds tones are generated. The frequency of one tone is known to be 610 Hz. The freque
1 answer:
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Answer:
It is producing either a 435-Hz sound or a 441-Hz sound.
Explanation:
When two sound of slightly different frequencies interfere constructively with each other, the resultant wave has a frequency (called beat frequency) which is equal to the absolute value of the difference between the individual frequencies:
(1)
In this problem, we know that:
- The frequency of the first trombone is
- 6 beats are heard every 2 seconds, so the beat frequency is
If we insert this data into eq.(1), we have two possible solutions for the frequency of the second trombone:
This question deals with the acceleration due to gravity on the surface of the planet. The value of the acceleration due to gravity on the surface of two planets, that is Earth and on the surface of another planet are compared to find out the relation between the radii of both planets, provided their masses are the same.
The correct option for the radius of the new planet is "Option 3: Square Root of 3 R"
The value of the acceleration due to gravity on the surface of a planet is given by the following formula:
----------- eqn(1)
where,
g = acceleration due to gravity on Earth
G = Universal Gravitational Constant
M = mass of the Earth
R = Radius of the Earth
Now, the same formula for the acceleration due to gravity on the surface of the other planet can be written as follows:
------------- eqn(2)
where,
g' = acceleration due to gravity on the new planet
G = Universal Gravitational Constant
M' = mass of the new planet
R' = Radius of the new planet
According to the given condition, the new planet has the same mass as the Earth's mass but the acceleration due to gravity on the surface of the new planet is one-third of the acceleration due to gravity on the surface of Earth.
using eqn (1) and eqn (2):
Hence, the radius of the new planet is found to be equal to the square root of 3 times the radius of the Earth (Square Root of 3 R).
Learn more about acceleration due to gravity on the surface of a planet here:
Answer:
<u><em>The plank moves 0.2m from it's original position</em></u>
Explanation:
we can do this question from the constraints that ,
- the wheel and the axle have the same angular speed or velocity
- the speed of the plank is equal to the speed of the axle at the topmost point .
thus ,
<em>since the wheel is pure rolling or not slipping,</em>
<em>⇒</em>
where
<em> - speed of the wheel</em>
<em> - angular speed of the wheel</em>
<em> - radius of the wheel</em>
<em>since the wheel traverses 1 m let's say in time '' ,</em>
<em></em>
∴
⇒
the speed at the topmost point of the axle is :
⇒
this is the speed of the plank too.
thus the distance covered by plank in time '' is ,
⇒