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maks197457 [2]
3 years ago
9

Craig has 20 video games. Out of these 20 video games, 45% are sports games.

Mathematics
1 answer:
Setler79 [48]3 years ago
4 0
20 games * 0.45 = 8 games.
shade 8 units
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What is wrong with the following proof? Clearly we know that 1 does not equal 2. What rule of algebra did we break that makes th
Gnoma [55]

An attempt to divide by zero gives a contradictory result

A rule of algebra broken is <u>dividing by zero</u> (leading to a contradiction) and stating a finite result

Reason:

The given calculation is presented as follows;

1. a > 0, b > 0 given

2. a = b given

3. a·b = b²

4. a·b - a² = b² - a²

5. a·(b - a) = (b + a)·(b - a)

6. a = b + a

7. 0 = b

8. b = 2·b

9. 1 = 2

From line 4, the result are;

4. a·b - a² = b² - a² = 0

5. a·(b - a) = (b + a)·(b - a) = 0

On line 6, both sides where divided by (b - a) = 0, which should given an infinite result

Therefore, one rule of algebra broken is dividing by zero to get a finite result

In line 7, we have;

7. 0 = b

From 6. a = b + a, and a = b, we have;

8. b = 2·b

Therefore, line 9 should be;

9. 0 = 2·0; 0 = 0, given that we have;

1 × 0 = 0

2 × 0 = 0

∴ 1 × 0 = 2 × 0

However

  • 1 ≠ 2

In line 9., by dividing by b = 0, again, we have;

  • 9. 1 = 2 (a contradiction)

Therefore, one rule of algebra that is broken is <u>dividing by zero</u> and having a finite result

Learn more about the rules of algebra here:

brainly.com/question/11388301

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3 years ago
Which list shows all the factors of 28?
yarga [219]
B. is your answer. :)
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Michael has eight coins of all which are quarters and pennies and all there were $1.76 how many of each kind of coin does Michae
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7 quarters and 1 penny
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3 years ago
Find the values of x and a please!!
Ludmilka [50]

Answer:

yes

Step-by-step explanation:

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3 years ago
An instructor who taught two sections of engineering statistics last term, the first with 20 students and the second with 30, de
Lelechka [254]

Answer:

(a) P(X=10) = 0.2070

(b) P(X\geq 10) = 0.3798

Step-by-step explanation:

Note that in this problem we have an initial population N = 50, of which 30 fulfill a certain characteristic "m" (belong to the second section). Then, from the population N, a sample of size n = 15 is selected and it is desired to know how many comply with the desired characteristic (second section).

So

Let X be the number of projects in the second section, then X is a discrete random variable that can be modeled by a hypergeometric distribution.

(a)

Therefore, to answer question (a) we use the following equation presented in the attached image:

Where:

N = 50\\m = 30\\n = 15\\X = 10

Then:

P (X = 10) = \frac{\frac{30!}{10!(30-10)!}\frac{20!}{5!(20-5)!}}{\frac{50!}{15!(50-15)!}}\\\\\\P(X=10) = 0.2070

(b)

For part (b) we have:

P(X\geq10) = 1-P(X

P(X\geq 10) = 1-0.6202 \\\\P(X\geq 10) = 0.3798

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3 years ago
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