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3 years ago

What information does a balanced equation provide?

Chemistry

2 answers:

Gelneren [198K]3 years ago

7 0

Explanation:

it has to have a problem base and a explanation.

MakcuM [25]3 years ago

6 0

Answer:

It has to have a problem base and a realistic explanation.

Explanation:

It needs to have enough information for you to be able to come up with an answer and realistic explanation.

Hope I helped :)

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The Tisza-Danube cyanide spill is an example of all of the following except a general pollution. b accidental pollution. c point

Serjik [45]

Answer: Its B!

Explanation:

4 0

2 years ago

What is the percentage of s-character in an sp hybrid? O 25% 50% o 75% O 66%

marishachu [46]

Answer: 50%

Explanation:

The number of electron pairs are 2 for hybridization to be $sp$ and the electronic geometry of the molecule will be linear.

1. percentage of s character in sp hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{2}\times 100=50\%$

2. percentage of s character in $sp^2$ hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{3}\times 100=33.3\%$

3. percentage of s character in $sp^3$ hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{4}\times 100=25\%$

Thus percentage of s-character in an sp hybrid is 50%.

8 0

3 years ago

What is the [H+] of a solution with a pH of 9.40?

LiRa [457]

Answer:

a) 3.98 x 10^-10

Explanation:

Hello,

In this case, for the given pH, we can compute the concentration of hydronium by using the following formula:

$pH=-log([H^+])$

Hence, solving for the concentration of hydronium:

$[H^+]=10^{-pH}=10^{-9.40}\\$

$[H^+]=3.98x10^{-10}M$

Therefore, answer is a) 3.98 x 10^-10

Best regards.

4 0

3 years ago

A solution contains [Ba2+] = 5.0 × 10−5 M, [Zn2+] = 2.0 × 10−7 M, and [Ag+] = 3.0 × 10−5 M. Sodium oxalate (Na2C2O4) is slowly a

Jet001 [13]

Answer:

BaC₂O₄, then ZnC₂O₄, then Ag₂C₂O₄

Explanation:

1. Calculate the equilibrium concentrations of oxalate ion

Let [C₂O₄²⁻] = c

(a) Barium oxalate

BaC₂O₄ ⇌ Ba²⁺ + C₂O₄²⁻

E/mol·L⁻¹: 5.0 × 10⁻⁵ c

Ksp = [Ba²⁺][C₂O₄²⁻] = 5.0 × 10⁻⁵c = 1.5 × 10⁻⁸

c = (1.5 × 10⁻⁸)/(5.0 × 10⁻⁵) = 3.0 × 10⁻⁴ mol·L⁻¹

(b) Zinc oxalate

ZnC₂O₄ ⇌ Zn²⁺ + C₂O₄²⁻

E/mol·L⁻¹: 2.0 × 10⁻⁷ c

Ksp = [Zn²⁺][C₂O₄²⁻] = 2.0 × 10⁻⁷c = 1.35 × 10⁻⁹

c = (1.35 × 10⁻⁹)/(2.0 × 10⁻⁷) = 6.8 × 10⁻³ mol·L⁻¹

(c) Silver oxalate

Ag₂C₂O₄ ⇌ 2Ag⁺ + C₂O₄²⁻

E/mol·L⁻¹: 3.0 × 10⁻⁵ c

Ksp = [Ag⁺]²[C₂O₄²⁻] = (3.0× 10⁻⁵)²c = 9.0 × 10⁻¹⁰c = 1.1 × 10⁻¹¹

c = (1.1 × 10⁻¹¹)/(9.0 × 10⁻¹⁰) = 0.012 mol·L⁻¹

2. Decide the order of precipitation

BaC₂O₄ will precipitate when c > 3.0 × 10⁻⁴ mol·L⁻¹

ZnC₂O₄ will precipitate when c > 6.8 × 10⁻³ mol·L⁻¹

Ag₂C₂O₄ will precipitate when c > 0.028 mol·L⁻¹

This happens to be the order of increasing concentration of oxalate ion.

The order of precipitation is

BaC₂O₄, then ZnC₂O₄, then Ag₂C₂O₄

4 0

3 years ago

What is the site of ATP synthesis

Fynjy0 [20]

ATP is synthesized in the mitochondria.
The mitochondria is known to be the powerhouse of a cell.

Hope it helped!

6 0

3 years ago

Read 2 more answers