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2 years ago

NAD+ and FAD are called ____

Chemistry

1 answer:

Evgesh-ka [11]2 years ago

4 0

Answer:

Nicotinamide adenine dinucleotide

Flavin adenine dinucleotide

Explanation:

hope this helps ^^

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At 25°C, gas in a rigid cylinder with a movable piston has a volume of 145 mL and a pressure of 125 kPa. Then the gas is compres

natta225 [31]

Answer:

(4) 230 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Divide both sides of the equation by $V_{2}$ .

$p_{2} = p_{1} \times \frac{V_{1}}{ V_{2}}$

$p_{1} = \text{145 kPa}; V_{1} = \text{125 cm}^{3}}$

$p_{2} = ?; V_{2} = \text{80. cm}^{3}$

$p_{2} = \text{145 kPa} \times \frac{\text{125 cm}^{3}}{\text{80. cm}^{3}} = \textbf{230 kPa}$

7 0

3 years ago

What is the chemical formula for zinc phosphate

igor_vitrenko [27]

<span>Zn3(PO4)2

hereugo!!!!!!!!!!</span>

8 0

3 years ago

Read 2 more answers

Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO

Irina-Kira [14]

Answer : The enthalpy of formation of $H_2SO_4$ is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of $H_2SO_4$ will be,

$S+H_2+2O_2\rightarrow H_2SO_4$ $\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

(1) $S+O_2\rightarrow SO_2$ $\Delta H_1=-298.2$

(2) $SO_2+\frac{1}{2}O_2\rightarrow SO_3$ $\Delta H_2=-98.2$

(3) $SO_3+H_2O\rightarrow H_2SO_4$ $\Delta H_3=-130.2$

(4) $H_2+\frac{1}{2}O_2\rightarrow H_2O$ $\Delta H_4=-285.8$

Now adding all the equations, we get the expression for enthalpy of formation of $H_2SO_4$ will be,

$\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4$

$\Delta H=(-298.2)+(-98.2)+(-130.2)+(-285.8)$

$\Delta H=-812.4kJ/mol$

Therefore, the enthalpy of formation of $H_2SO_4$ is, -812.4 kJ/mole

3 0

3 years ago

The following conditions exist in a bacterium and its environment. Environment: 5M NaCl; 1M glucose Inside cell: 3M NaCl; 10M gl

NARA [144]

Answer:

False

Explanation:

Diffusion uses the concentration gradient that has been set up, this is a naturally occurring phenomena, and using a diffusion gradient some small particles can cross over the cell membrane. Some bigger or polar molecules require facilitated diffusion to move these molecules across the membrane.

Facilitated diffusion still uses the gradient for passive transport. This means that ATP is not used to transport molecules.

The reason that glucose will not move into the cell via passive transport is because there is a higher concentration of glucose inside the cell, meaning it needs active transport to move glucose (against the concentration gradient) into the cell.

3 0

3 years ago

What is the amount in moles of a 52 g sample of aluminium fluoride, AIF3

Karo-lina-s [1.5K]

Answer:

Try looking for some kind of answer that has to do with .61904

Explanation:

52 g x 1 mol/ (molar mass of aluminum fluoride) 84 g = .619047619

Sorry if this is wrong but that's my best guess

6 0

2 years ago