Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:
C1V1 = C2V2
(6.0M)(2.0mL) = C2(500.0mL)
Therefore, the final concentration, C2 = 0.024M.
Approximating 7 to 20 kilometers
Hope this helps
Explanation:
vertical columns and horizontal rows, hope it helps
According to Data,
Mass Number = 65
# of Neutrons = 35
As we know,
Mass Number = # of protons + # of Neutrons
Solving for # of protons,
# of protons = Mass Number - # of Neutrons
Putting values,
# of Protons = 65 -35
# of protons = 30
As,
# of protons is the atomic number, so element with atomic number 30 is Zinc.
The cation derived from it has 28 electrons,
So, Zinc having 30 electron will be left with two extra protons, and each proton has +1 charge.
Result:
Zn²⁺
