All categories

3 years ago

Why is corn considered a material resource and an energy resource?

Chemistry

1 answer:

MakcuM [25]3 years ago

3 0

Answer:

This is because Corn is grown on land and has important values to man .These values include as a source of food for man and animals. It is also used as raw materials for the production of certain goods such as flour etc.

It is an energy resource because fermentation of corn gives rise to ethanol fuel which is used as a source of power to run machines and other equipment.

You might be interested in

The chemical equation of photosynthesis includes 6O2. What does the small number after the O represent?

blondinia [14]

Its the number of Oxygen molecules

3 0

4 years ago

A 33.153 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap

elena-14-01-66 [18.8K]

Answer:

The empirical formula of the compound = $C_4H_8S_1O_1$

Explanation:

Mass of carbon dioxide gas = 59.060 mg = 0.059060 g

1 mg = 0.001 g

Moles of carbon dioxide = $\frac{0.059060 g}{44 g/mol}=0.0013 mol$

Moles of carbon in 0.0013 moles of carbon dioxide gas = 1 × 0.0013 mol = 0.0013 mol

Mass of 0.0013 moles of carbon = $12 g/mol\times 0.0013 mol=0.0156 g$

Mass of water = 24.176 mg = 0.024176

Moles of water = $\frac{0.024176 g}{18 g/mol}=0.0013 mol$

Moles of hydrogen in 0.0013 moles of water = 2 × 0.0013 mol = 0.0026 mol

Mass of 0.0013 moles of hydrogen= $1 g/mol\times 0.0013 mol=0.0013 g$

Mass of sulfur dioxide = 20.326 mg = 0.020326 g

Moles of sulfur dioxide = $\frac{0.020326 g}{64 g/mol}=0.00032 mol$

Moles of sulfur in 0.00032 moles of sulfur dioxide = 1 × 0.00032 mol = 0.00032 mol

Mass of 0.00032 moles of sulfur = $32 g/mol\times 0.00032 mol=0.01024 g$

Mass of oxygen in the sample = x

Mass of sample = 33.153 mg = 0.033153 g

0.033153 g = 0.0156 g + 0.0013 g + 0.01024 g + x

x = 0.006013 g

Moles of oxygen = $\frac{0.006013 g}{16 g/mol}=0.00038 mol$

For empirical formula divide the lowest number of moles of elemnt from all the moles of the all the elements:

Carbon : $\frac{0.0013 mol}{0.00032 mol}=4$

Hydrogen: $\frac{0.0026 mol}{0.00032 mol}=8$

Sulfur : $\frac{0.00032 mol}{0.00032 mol}=1$

Oxygen : $\frac{0.00038 mol}{0.00032 mol}=1$

The empirical formula of the compound = $C_4H_8S_1O_1$

8 0

4 years ago

How do Earth's lithosphere,hydrosphere,and atmosphere compare?

Oduvanchick [21]

<span>the lithosphere, which contains all of the cold, hard, solid rock of the planet's crust (surface), the hot semi-solid rock that lies underneath the crust, the hot liquid rock near the center of the planet, and the solid iron core (center) of the planet </span>the hydrosphere, which contains all of the planet's solid, liquid, and gaseous water,and the atmosphere, which contains all of the planet's air

6 0

4 years ago

Read 2 more answers

Will the volume of a 1.0 L sample of gas at STP change if the pressure and temperature are both doubled

Dmitry_Shevchenko [17]

Answer:

The volume will not change. This belongs in Ripley's Believe It or Not.

Explanation:

The combined gas law can be used to model both the initial (1) and ending (2) states of a gas when pressure (P), temperature (T) and/or volume (V) change, but the number of moles does not. Remember that temperature must always be in Kelvin.

P1V1/T1 = P2T2/T2

Rearranging for V2:

V2 = V1(T2/T1)(P1/P2)

I've arranged the pressure and temperature terms as ratios. This makes it easier to see what impact changes will have, plus the units conveniently cancel for both.

(V2) = (1 L)(T2/T1)(P1/P2)

We are told that P2 and T2 are both doubled:

(T2/T1) = 2

(P1/P2) = 1/2

V2 = (1 L)(T2/T1)(P1/P2)

V2 = (1 L)(2)(1/2)

V2 - 1 L

The volume does not change. Bummer.

7 0

2 years ago

20 cubic inches of a gas with an absolute pressure of 5 psi is compressed until its pressure reaches 10 psi. What's the new volu

belka [17]

10 cubic inches
We will use Boyle's law that states that for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional.
P1 V1 = P2 V2
Where
P1 is initial pressure = 5 psi
V1 is initial volume = 20 cubic inch
P2 is final pressure = 10 psi
V2 is final volume = unknown
V2 = P1,V1 / P2
V2 = 20 × 5 / 10
V2 = 100/10
V2 = 10 cubic inches

7 0

3 years ago