Answer:
Calcium chlorate | Ca(ClO3)2 - PubChem.
Explanation:
Answer:
0.50 g of Na Metal
Solution:
The equation for given reaction is as follow,
2 NaN₃ → 2 Na + 3 N₂
According to equation,
When,
67.2 L (3 mole) N₂ is produced along with = 46 g (2 mole) of Na Metal
So,
0.744 L N₂ produced will accompany = X g of Na Metal
Solving for X,
X = (0.744 L × 46 g) ÷ 67.2 L
X = 0.50 g of Na Metal
Molality can be expressed by moles of solute over
kilograms of solvent. The question asks the molality of 0.25m NaCl. 0.25m NaCl
is equal to 0.25 moles of NaCl over 1 kg of water.
Answer:
So the molar mass of C4,H10 is
58.12g mole -1
The answer is 800J
jciuytwujerfgyb7ruhufyewhjr7fhewryuhf(My answer was to short)