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katrin [286]
3 years ago
12

How much heat is required to heat the temperature of 338g of aluminum by?

Physics
1 answer:
enyata [817]3 years ago
3 0
Specific heat<span> is another physical property of matter. ... we con now ask the following question: by </span>how much<span> will the </span>temperature<span> of an .</span>
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Explanation: Hope this help! :)

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What relates the net force exerted on an object to its mass and acceleration?
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85

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3 years ago
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

    The mass of the arm is m_a  = 4.0 \  kg

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

       r = \frac{l}{2}

=>    r = \frac{ 0.7}{2}  

=>    r = 0.35 \ m  

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

5 0
3 years ago
Please hurry!!!
Nikolay [14]
First we need to know the equation which is P=mv
Use the formula- 3.2 kg x m/s = 762 x V
divide 762 in both side to get the v by itself
now we will have 0.004193971166 and lets round it!
then we will have the answer of .0042
3 0
3 years ago
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