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Bas_tet [7]
2 years ago
7

Question 2 of 34

Physics
1 answer:
tatiyna2 years ago
8 0

You can find the magnitude of the resultant vector : (B). By adding the magnitudes of the two vectors

<h3>Meaning of Vectors</h3>

A vector can be defined as any quantity which possesses magnitude and also has direction.

A Vector quantity is very useful because This type of quantity gives more details to the student or teacher analyzing it.

Lear more about Vectors: brainly.com/question/25705666

#SPJ1

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A harmonic wave on a string with a mass per unit length of 0.050 kg/m and a tension of 60 N has an amplitude of 5.0 cm. Each sec
Dennis_Churaev [7]

Answer:

Power of the string wave will be equal to 5.464 watt

Explanation:

We have given mass per unit length is 0.050 kg/m

Tension in the string T = 60 N

Amplitude of the wave A = 5 cm = 0.05 m

Frequency f = 8 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 8=50.24rad/sec

Velocity of the string wave is equal to v=\sqrt{\frac{T}{\mu }}=\sqrt{\frac{60}{0.050}}=34.641m/sec

Power of wave propagation is equal to P=\frac{1}{2}\mu \omega ^2vA^2=\frac{1}{2}\times 0.050\times 50.24^2\times 34.641\times 0.05^2=5.464watt

So power of the wave will be equal to 5.464 watt

6 0
2 years ago
How many pets do you have???!!!??
jasenka [17]

Answer:

Right now I have three.

Explanation: Thanks for the points luv ^-^.

5 0
3 years ago
Read 2 more answers
If there is no slipping, a frictional force must exist between the wheels and the ground. in what direction does the frictional
djyliett [7]
The frictional force is always act in opposite direction of motion. if wheels is moving in +x axis or right then the f force is act in -x or left
8 0
3 years ago
1. What coefficients would balance the following equation?
Stolb23 [73]

Answer:

no question matee

Explanation:

3 0
2 years ago
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A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. What is the m
Akimi4 [234]

Answer:

8.6 m

Explanation:

The motion of a soccer ball is a motion of a projectile, with a uniform motion along the horizontal (x-) direction and an accelerated motion along the vertical (y-) direction, with constant acceleration a=g=-9.8 m/s^2 towards the ground (we take upward as positive direction, so acceleration is negative).

The initial velocity along the vertical direction is

v_{y0} = v_0 sin \theta = (26 m/s)(sin 30^{\circ})=13 m/s

Now we can consider the motion along the vertical direction only. the vertical velocity at time t is given by:

v_y(t)=v_{y0} +at

At the point of maximum height, v_y(t)=0, so we can find the time t at which the ball reaches the maximum height:

0=v_{y0}+at\\t=-\frac{v_{y0}}{a}=-\frac{13 m/s}{-9.8 m/s^2}=1.33 s

And now we can use the equation of motion along the y-axis to find the vertical position of the ball at t=1.33 s, which corresponds to the maximum height of the ball:

y(t)=v_{y0}t + \frac{1}{2}at^2=(13 m/s)(1.33 s)+\frac{1}{2}(-9.8 m/s^2)(1.33 s)^2=8.6 m

4 0
2 years ago
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