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vaieri [72.5K]
3 years ago
8

Isim sehir eyşa iiiiiiiimi iiiiooiiii​

Physics
1 answer:
kolezko [41]3 years ago
6 0

walkyshlusha and the

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a racing car undergoes a uniform acceleration of 4.00m/s2. if the net force causing the acceleration is 3.00 times 10^3 N, what
yKpoI14uk [10]

Answer: 750Kg

Explanation:

Recall that force is the product of the mass M, of an object moving at a uniform acceleration.

i.e Force = Mass x Acceleration

In this case, Mass = ?

Force = 3.00 x 10^3 N = (3.00 x 1000N)

= 3000N

Uniform acceleration = 4.00m/s^2

Force = Mass x Acceleration

3000N = Mass x 4.00m/s^2

Mass = (3000N/4.00m/s^2)

Mass = 750Kg (The SI unit of mass is kilograms)

Thus, the mass of the car is 750Kg

4 0
3 years ago
A hydrogen bomb has a diameter of about 10nm express this in meters
GenaCL600 [577]
1 Nautical metre=1852 metres
10×1852
=18520 metres
3 0
3 years ago
Please answerASAP
Illusion [34]

Answer:

8.9 m/s^2

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the lenght of the pendulum

g is the acceleration due to gravity at the location of the pendulum

We notice from the formula that the period of a pendulum does not depend on the mass of the system

In this problem:

-The pendulum comes back to the point of release exactly 2.4 seconds after the release. --> this means that the period of the pendulum is

T = 2.4 s

- The length of the pendulum is

L = 1.3 m

Re-arranging the equation for g, we can find the acceleration due to gravity on the planet:

g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{2.4})^2(1.3)=8.9 m/s^2

7 0
4 years ago
6. When a positive charge is released and moves along an electric field line, it moves to a position of A) lower potential and l
Marysya12 [62]

Answer:

Since you would have to do work on the charge to bring it back to its original position, the charge moves to a position of lower potential and lower potential energy.

4 0
3 years ago
How does an inclined plane trade force for distance??
liq [111]
The sloping surface of the inclined plane<span> supports part of the weight of the object as it moves up the slope. As a result, it takes less </span>force<span> to move the object uphill. The </span>trade<span>-off </span>is<span> that the object must be moved over a greater </span>distance<span> than if it were moved straight up to the higher elevation.</span>
8 0
4 years ago
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