Water flowing through a small creek into a stream after a storm is an example of ____

Which model could represent a neutral atom of oxygen?<br> A. 2<br> B. 4<br> C. 3<br> D. 1

Sergeu [11.5K]

Answer: D. 1

Explanation:

Choice 1 could represent a neutral atom of oxygen

4 0

3 years ago

Read 2 more answers

If a current of 2.0 A is flowing from point a to point b, the potential difference between Vb- Va (in V) is:

Aliun [14]

Answer:

$\huge\color{skyblue}\boxed{\colorbox{black}{Answer ☘}}$

$total \: resistance \: ( R_{t} ) = (3 + 1)ohm \\ (since \: the \: resistors \: are \: connected \\ in \: series)$

$current \: flowing \: through \: circuit(I) = 2A \\ \\ now... \: by \: ohms \: law \\ V = IR\\ V = (2)(4) \\ = > 8v$

<h3>therefore , option (b) is correct!!</h3>

hope helpful~

5 0

2 years ago

The two major components of the Earth's atmosphere are _____ and _____.

Sever21 [200]

Earth's atmosphere is made up of a combination of gases. The major components of nitrogen, oxygen, and argon remain constant over time and space, while trace components like CO2 and water vapor vary considerably over both space and time.

4 0

3 years ago

A block slides to a stop as it goes 47 m across a level floor in a time of 6.35 s. a) What was the initial velocity? b) What is

UNO [17]

Answer :

(a) The initial velocity is, 14.8 m/s

(b) The acceleration is, $-2.33m/s^2$

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 0 s

u = initial velocity

t = time = 6.35 s

a = acceleration

The equation 1 will be:

$0=u+a(6.35}$

$u=-6.35a$ ..........(2)

By the 2nd equation of motion,

$s=ut+\frac{1}{2}at^2$ ...........(3)

where,

s = distance = 47 m

Now substitute equation 2 in 3, we get:

$47=(-6.35a)\times (6.35)+\frac{1}{2}\times a\times (6.35)^2$

By solving the term, we get:

$a=-2.33m/s^2$

The acceleration is, $-2.33m/s^2$

Now we have to calculate the initial velocity.

Using equation 2, we gte:

$u=-6.35a$

$u=-6.35s\times (-2.33m/s^2)$

$u=14.8m/s$

The initial velocity is, 14.8 m/s

5 0

3 years ago

Two students try to move a heavy box. One pushes with the force of the 80N while the other pulls with a force of 40N in the same

alekssr [168]

Answer:

Explanation:

Force applied by first student (F1) = 80 N

Force applied by the second student (F2) = 40 N

Displacement (d) = 10 m

Work done by first student (W1) = F1d = 80*10 = 800 J

Work done by second student (W2) = F2d = 40*10 = 400 J

Hence, the work done by the pushing student is 800 J and that by pulling student is

5 0

3 years ago

Water flowing through a small creek into a stream after a storm is an example of _____.