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3 years ago

Please help me (￣ ‘i ￣;)

Mathematics

2 answers:

expeople1 [14]3 years ago

8 0

Answer:

-6 + 4 = -2

Step-by-step explanation:

Just start from -6 then go to the right four places and you'll get -2

Anna [14]3 years ago

7 0

Answer:

-6 + 4 = -2

Step-by-step explanation:

I know.

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30 points.. Please Help! I don't understand what to do with this question...a bit confused.

Romashka-Z-Leto [24]

Eh, here's my best try for a table:

Like tv don't like tv total
Like reading: 70 10 80
Don't like read. 20 30 50 
total 90 40 130

The percentage of students that like tv as well as reading is- 70 divided by 130 which gives you .538 which in percentage is 53.8%.

The probability of a student that does not prefer to watch tv as also does not like to spend their time reading is 30 over 40 which can be simplified or reduced to 3 over 4. [30/40 reduced to 3/4]

Hope this somehow helped you :)

5 0

3 years ago

36.Simplify: 5 – {3 – (x - 8) }

Alecsey [184]

Answer:

x-10

Step-by-step explanation:

you have to do what is in the parenthesis first. Do distributive property to

-(x-8)

-(x)-(-8)= -x+8

now you have 5-(3-x+8)

Do distributive property again

5-3+x-8

x-8+2

x-10

hope this helps ~D~

5 0

3 years ago

Read 2 more answers

n = 23 H0: σ2 ≥ 66 s2 = 60 Ha: σ2 < 66 The test statistic has a value of _____. a. 24.20 b. 24.00 c. 20.91 d. 20.00

Arada [10]

Answer:

$\chi^2 =\frac{23-1}{66} 60 =20.00$

d.20.00

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=23$ represent the sample size

$\alpha$ represent the confidence level

$s^2 =60$ represent the sample variance obtained

$\sigma^2_0 =66$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance is less than 66, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 66$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{23-1}{66} 60 =20.00$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 23-1=22. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$