Temporarily subdivide the given area into two parts: a large rectangle and a parallelogram. Find the areas of these two shapes separately and then combine them for the total area of the figure.
By counting squares on the graph, we see that the longest side of the rectangle is the hypotenuse of a triangle whose legs are 8 and 2. Applying the Pyth. Thm., we find that this length is √(8^2+2^2), or √68. Similarly, we find the the width of this rectangle is √(17). Thus, the area of the rectangle is √(17*68), or 34 square units.
This leaves the area of the parallelogram to be found. The length of one of the longer sides of the parallelogram is 6 and the width of the parallelogram is 1. Thus, the area of the parallelogram is A = 6(1) = 6 square units.
The total area of the given figure is then 34+6, or 40, square units.
Answer:
192,000 grams
Step-by-step explanation:
turn 1,344 kilograms to grams, which gives u 1344000 grams
divide 1344000 by 7 and you get 192,000 grams. Hope this helped :)
Answer:
I believe D is the answer. (Triangles BPA and DPC are congruent.)
Angles BAD and ADC are not congruent.
Sides CD and DA are also not congruent
-2x + 6y = -34
-x + 3y = -17
x = 3y +17
Sub this into 1st eqn
5(3y + 17) + 2y = 21
15y + 85 + 2y =21
17y = -64
y = -3.7647 (to 5 sig. fig.)
y = -3.8 (to nearest tenth)
Sub y = -3.7647 into 2nd eqn
x = 3(-3.7647) +17
x = 5.7 (to nearest tenth)
-6, because you can see a pattern in which the x coordinate of each pair is reversed to the opposite value, from positive to negative.
