Alright, so we'll be playing a little with variables around here. The question tells you the length of a rectangle is six times its width, or that l=6w.
The perimeter of a rectangle is 2l + 2w (two times the length + two times the width). Since we established that l=6w...
2(6w) + 2w = 98 yd
12w + 2w = 98 yd
14w=98 yd
w=7 yd.
But it doesn't stop there. We found that the width is 7 yd. So the length is 6w, or 6 x 7 yd, which is 42 yd. To find the area of a rectangle, you multiply the length by the width.
So...42 yd x 7 yd = 294 yd^2.
Hope that helped.
Answer:
um sorry cant help I spaced lol
Answer:
21.44 ft
Step-by-step explanation:
(sketch to understand)
use SOH/CAH/TOA rules to solve
sin rule is used
solve for x
(working in the picture attached)
The correct answer is 10 \8.
X= 9th student test score
Add the 9 test scores and divide that total by 9 to equal the average.
(56 + 92 + 78 + 64 + 85 + 83 + 91 + 77 + x)/9= 78
add in parentheses
(626 + x)/9= 78
multiply both sides by 9
626 + x= 702
subtract 626 from both sides
x= 76
ANSWER: 76 is the score needed by the 9th student for a mean of 78.
Hope this helps! :)
