It is given that line segment BC is congruent to line segment EC and that line segment AC is congruent to DC. Because of the vertical angles theorem, angle BCA is equal to angle DCE. Therefore, triangles CBA AND DEC are congruent by SAS. Using CPCTC, BA is equal to ED.
<span>The point of concurrency of the three medians of a triangle is called the orthocenter of the triangle.</span>
Answer: Equations (b) and (e) do not have solutions
Step-by-step explanation: b) The x cancels out (-10x + 35) = -10x + 318; 35 = 318???? NO. e) 3(x + 2) + 1 = x + 2(4 + x); 3x + 7 = 3x + 8. The x cancels out again.
The other s can be solved for x.
The answer is 8n2 + 26n + 6
Answer:
2/7
Step-by-step explanation:
1
2
÷
1 3
4
=
1
2
÷
7
4
=
1
2
×
4
7
=
1 × 4
2 × 7
=
4
14
=
4 ÷ 2
14 ÷ 2
=
2
7
