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ad-work [718]
4 years ago
13

A 106 kg clock initially at rest on a horizontal floor requires a 670 N horizontal force to set it in motion. After the clock is

in motion, a horizontal force of 557 N keeps it moving with a constant velocity.
a) what is the μs between the clock and the floor?.70
b) what is the μk between the clock and the floor?
Physics
1 answer:
kolezko [41]4 years ago
5 0

Answer:

a) \mu_s=0.65

b) \mu_k=0.54

Explanation:

Static friction is when the body is at rest or is about to move while kinetic friction is when the body is already in motion. According to Newton's second law:

\sum F_y:N=mg\\\sum F_x:F_f=F_x

a)  In this case, the static friction must be equal to the horizontal force to set the clock in motion:

F_f=\mu_sN=\mu_smg\\\mu_smg=F_x\\\mu_s=\frac{F_x}{mg}\\\mu_s=\frac{670}{106kg(9.8\frac{m}{s^2})}\\\mu_s=0.65

b) In this case, the kinetic friction is equal to the horizontal force that keep the clock moving with constant velocity:

\mu_kmg=F_x'\\\mu_k=\frac{F_x'}{mg}\\\mu_k=\frac{557}{106kg(9.8\frac{m}{s^2})}\\\mu_k=0.54

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