4 years ago

What happens to an object at rest if there is no net force on the object?

Physics

1 answer:

sp2606 [1]4 years ago

8 0

Answer:it will continue in its state of rest.

Explanation:

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Daisy walks across a force platform, and forces exerted by her foot during a step are recorded. The peak velocity reaction force

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Answer:

(a). The resultant of these forces is 1216.55 N.

(b). The direction of the resultant forces is 80.53°.

Explanation:

Given that,

First force = 1200 N

Second force = 200 N

(a). We need to calculate the resultant of these forces

Using cosine law

$F=\sqrt{F_{1}^2+F_{2}^2+2F_{1}F_{2}\cos\theta}$

Put the value into the formula

$F=\sqrt{1200^2+200^2+2\times1200\times200\cos90}$

$F=\sqrt{1200^2+200^2}$

$F= 1216.55\ N$

The resultant of these forces is 1216.55 N.

(b). We need to calculate the direction of the resultant forces

Using formula of direction

$\tan\alpha=\dfrac{F_{1}}{F_{2}}$

Put the value into the formula

$\alpha=\tan^{-1}(\dfrac{1200}{200})$

$\alpha=80.53^{\circ}$

Hence, (a). The resultant of these forces is 1216.55 N.

(b). The direction of the resultant forces is 80.53°.

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4 years ago

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If a car is accelerating downhill under a net force of 3674 N, what force must the brakes exert to cause the car to have constan

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Answer:

Explanation:

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3 years ago

Is it possible for you to take a hike and have the distance you cover be equal to the magnitude of your displacement?

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Distance can be equal to displacement ... if the motion is all in a straight line ... but distance can never be greater than displacement.

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A greyhound's velocity changes from 10 meters per second to 15 meters per second in 0.5 second. What is the greyhound's average

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The answer would be 10ms 2

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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.60 mm. If a

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Answer:

Explanation:

(a) For the calculation of the Electric field we use

$E=\frac{V}{d}=\frac{15.0V}{1.6*10^{-3}m} =9375\frac{N}{C}$

(b) The capacitance is calculate by using the expression

$C=\frac{\epsilon_{0}A}{d}=\frac{8.85*10^{-12}C^{2}/(Nm^{2})*(7.6*10^{-4}m^{2})}{1.6*10^{-3}m}=4.2*10^{-12}C$

(c) Finally, the charge on each plate is

$Q=CV=(4.2*10^{-12}C)(15V)=6.3*10^{-11}C$

I hope this is useful for you

Regards

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3 years ago

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