Question

The Sun delivers an average power of 15.29 W/m2 to the top of Saturn's atmosphere. Find the magnitudes of vector E max and vector B max for the electromagnetic waves at the top of the atmosphere.

Answer 1

Answer:

$E=\sqrt{\frac{2u_E}{\epsilon_0}}=1.8*10^6N/C\\B=\sqrt{2\mu_0}=1.58*10^{-3}T$

Explanation:

The energy density of electromagnetic waves can be computed as

$u_{E}=\frac{1}{2}\epsilon_0E^2\\u_B=\frac{B^2}{2\mu_0}$

The power is the energy per unit of time. Hence we can take uE and Ub as 15.29J

By taking apart E and B we have

$E=\sqrt{\frac{2u_E}{\epsilon_0}}=1.8*10^6N/C\\B=\sqrt{2\mu_0}=1.58*10^{-3}T$

hope this helps!!

Answer 2

Answer:

$E_{max} = 107.37N/C$

$B_{max} = 35.79\times 10^-^8T$

Explanation:

$I_{avg}=\frac{E_{max}^2}{2u_0C}$

$E_{max} =\sqrt{2u_0CI_{avg}} }\\\\= \sqrt{2\times4\pi \times10^-^7\times3\times10^8\times 15.29} \\\\E_{max} = 107.37N/C$

b)

$B_{max}=\frac{E_{max }}{C}$

$B_{max} = \frac{107.37}{3\times10^8} \\\\= 35.79\times 10^-^8T$