Same formula as the last question. x = vt + (1/2)at^2. In this case, v = 0, t = 12, and a = 2.0. Plug in the values and solve for x (which is change in position)
x = (0)(12) + (1/2)(2.0)(12^2)
x = (1/2)(2.0)(144)
x = (1)(144)
x = 144
So the car will travel 144 meters in 12 seconds.
Given that,
Mass of a boy = 50 kg
The coefficient of static friction = 0.68
To find,
Let us assume we need to find the maximum static friction between the boy and the ground.
Solution,
The formula for the maximum static friction between the two objects is given by :

Where
N is normal force
Substitute all the values,

Therefore, the maximum static friction between the boy and the ground is 340 N.
Answer:
Entropy is 14.17 J/k
Explanation:
The entropy change associated with the expansion of gas from v to 5.5v is given by
S=Rin(Vf/Vi)
We're Vi= iniatial volume and Vf is final volume
Hence S= 8.314in(5.5v/v)
S=14.17J/K
Answer:
Explanation:
The amplitude of a wave refers to the maximum amount of displacement of a particle on the medium from its rest position.
Answer: 
Explanation:


We have a negative acceleration, meaning that the car is slowing down.