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3 years ago

HEYY PLEASE HELP ME!! +50 POINTS!!! WILL GIVE BRANLIEST IF CORRECT!!

Physics

2 answers:

GarryVolchara [31]3 years ago

8 0

Answer: 12

Explanation: Divide it up into sections and multiply and divide.

sashaice [31]3 years ago

4 0

Answer:

I think it is 12

Explanation:

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How does energy relate to force?

ioda

Answer:work is force times distance

Explanation:to create a force u need energy and the greater the energy the greater the force is applied to an object.

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3 years ago

In a horizontal pipe with a gradually decreasing cross-section (in the direction of flow) there is a clear fluid of unknown dens

qwelly [4]

Answer:

the density of this clear fluid is 1140.35 kg/m^3

Explanation:

Given that :

$P_p = P__{Q}} + 260 \ Pa \\ \\ v_p =0.37 \ m/s \\ \\ v_Q = 0.77 \ m/s$

According to Bernoulli's Equation.

$P_p + \frac{1}{2} pv^2_p+pgh_p= P_Q+ \frac{1}{2} pv^2_Q + pgh_Q$

∴ $260 = \frac{1}{2}p (v^2_Q-v^2_p)$ since ( $h_p = h_Q$ )

$\rho = \frac{2(260)}{v^2_Q-v^2_p}$

$\rho = \frac{2(260)}{0.77^2-0.37^2}$

$\rho = \frac{520}{0.5929-0.1369}$

$\rho =$ $1140.35 \ kg/m^3$

5 0

4 years ago

Free points im poor so only 9

mash [69]

Answer:

i feel bad

Explanation:

7 0

4 years ago

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In a cyclotron, the orbital radius of protons with energy 300 keV is 16.0 cm . You are redesigning the cyclotron to be used inst

dem82 [27]

Answer:

$r_\alpha=16cm$

Explanation:

The radius of the circumference described by a particle in a cyclotron is given by:

$r=\frac{mv}{qB}(1)$

m is the particle's mass, v is the speed of the particle, q is the particle's charge and B is the magnitude of the magnetic field.

Kinetic energy is defined as:

$K=\frac{mv^2}{2}=\frac{m^2v^2}{2m}\\$

Solving this for mv:

$mv=\sqrt{2mK}(2)$

Replacing (2) in (1):

$r=\frac{\sqrt{2mK}}{qB}$

For protons, we have:

$r_p=\frac{\sqrt{2m_pK}}{eB}(3)$

For alpha particles, we have:

$r_\alpha=\frac{\sqrt{2m_\alpha K}}{(2e)B}(4)$

Dividing (4) in (3):

$\frac{r_\alpha}{r_p}=\frac{\frac{\sqrt{2m_\alpha K}}{(2e)B}}{\frac{\sqrt{2m_p K}}{(e)B}}\\r_\alpha=\frac{r_p}{2}\sqrt{\frac{m_\alpha}{m_p}}\\r_\alpha=\frac{16cm}{2}\sqrt{\frac{6.64*10^{-27}kg}{1.67*10^{-27}kg}}\\r_\alpha=\frac{16cm}{2}(\sqrt{3.98})\\\\r_\alpha=\frac{16cm}{2}(2)\\r_\alpha=16cm$

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4 years ago

In a certain city, electricity costs $0.13 per kW·h.

Alex_Xolod [135]

The question is asking to compute the annual cost of electricity to power a lamp post for 7.5 hrs per day with the following power, and base on my calculation, the answers would be the following:
#1. 7,580,769.23
#2. 1,895,195.31
I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications.

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3 years ago

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