Find the smallest positive integer divisible by $10$, $11$, and $12$.
1 answer:
Answer:
Smallest divisible number = 660
Step-by-step explanation:
Given:
Numbers
10, 11, 12
Find:
Smallest divisible number
Computation:
Factor
10 = 2×5
11 = 11×1
12 = 2×2×3
Smallest divisible number = 2×2×3×5×11
Smallest divisible number = 660
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