3 years ago

Find the smallest positive integer divisible by $10$, $11$, and $12$.

Mathematics

1 answer:

Leya [2.2K]3 years ago

3 0

Answer:

Smallest divisible number = 660

Step-by-step explanation:

Given:

Numbers

10, 11, 12

Find:

Smallest divisible number

Computation:

Factor

10 = 2×5

11 = 11×1

12 = 2×2×3

Smallest divisible number = 2×2×3×5×11

Smallest divisible number = 660

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