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nevsk [136]
4 years ago
8

A heat engine operates between a hot reservoir with a temperature of 400 K and a cold reservoir with a temperature of 300 K. The

engine accepts 500 J of energy from the hot reservoir, does 150 J of work, and exhausts 350 J of energy into the cold reservoir. 1) Does this engine violate any laws of thermodynamics?
Physics
1 answer:
natali 33 [55]4 years ago
3 0

Answer:

Explanation:

Given

Temperature of Hot reservoir T_1=400 K

Temperature of Cold reservoir T_2=300 K

Heat reservoir Q=500 J

Work done W=150 J

heat Exhaust Q_{rejection }=350 J

Q=W+Q_{rejected}

500=150+350

L.H.S=R.H.S

thus it follows first law

\eta _{carnot}=1-\frac{T_L}{T_H}

\eta _{carnot}=1-\frac{300}{400}

\eta _{carnot}=0.25

Cycle Efficiency

\eta =\frac{W}{Q}=\frac{150}{500}=0.3

Carnot efficiency is less than cycle thus it violates second law

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