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forsale [732]
3 years ago
11

Which is an example of a scientist using a mathematical model to describe the weather?

Physics
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

The scientist finds an equation that predicts how long the rainstrom will last.

Explanation:

I just answered it :)

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A student pushes against a wall with a force of 30N. The wall does not move. What amount of force does the wall exert on the stu
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Answer:

C

Explanation:

they both have to be the same for both to not move

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2 years ago
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Explain why the ion formed has a positive charge
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When an ion is formed, the number of protons does not change. ... By removing an electron from this atom we get a positively charged Na+ ionthat has a net charge of +1. Atoms that gain extra electrons become negatively charged. A neutral chlorine atom, for example, contains 17 protons and 17 electrons.
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Leah is making a chart to compare and contrast renewable and non-renewable resources. Which of the following would best complete
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Answer:

d. Can be replaced at the same rate or faster than they are used

Explanation:

I just took the test, and its the right answer. Your welcome ✌

6 0
3 years ago
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how do u calculate the kinetic energy of a ball of mass 0.25kg being kicked vertically upwards with a speed of 5m/s​
vfiekz [6]

Answer:

3.125J

Explanation:

K.E.= 1/2(mass)(velocity)^2

K.E.=1/2(0.25)(5)^2=3.125

6 0
3 years ago
A 0.245 kg ball is thrown straight up from 2.07 m above the ground. Its initial vertical speed is 8.00 m/s. A short time later,
iris [78.8K]

Answer:

The work done by gravity is 4.975 \: Joules

Explanation:

The data given in the question is :

Mass is 0.245 kg

Height from ground is 2.07 m

As we know , the work done is state function , it depends on initial and final position not on the path followed.

So, work done by gravity = change in potential energy

Work done = Initial potential energy - final potential energy

Insert values from question

Work done = mass \times gravity \times (change \: in \: height)

Work done = 0.245 kg \times 9.81 m/s^{2} \times 2.07 m

So, work done = 4.975 Joules

Hence the work done by gravity is 4.975 \: Joules

3 0
4 years ago
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