Answer:
0.25m²
Explanation:
We know that the summation of forces in the vertical direction is zero
So
PA-mg=0
A=mg/p
So
Substituting
A= 75* 9.8/3*10^-3
=0.25m² which is the total shoe area
Answer:
Initial Velocity is 4 m/s
Explanation:
What is acceleration?
It is the change in velocity with respect to time, or the rate of change of velocity.
We can write this as:
Where
a is the acceleration
v is velocity
t is time
is "change in"
For this problem , we are given
a = 1.2
t = 10
Putting into formula, we get:
So, the change in velocity is 12 m/s
The change in velocity can also be written as:
It is given Final Velocity = 16, so we put it into formula and find Initial Velocity. Shown Below:
hence,
Initial Velocity is 4 m/s
Answer:
Explanation:
i )
When it is disconnected with the battery , the charge stored in it becomes fixed . When the plate distance becomes half , its capacitance becomes twice from C to 2C . Let charge stored in it at the time of disconnection from battery be Q . Let plate separation reduces from d to d / 2
So charged stored in it will remain unchanged .
ii )
Potential difference = charge / capacitance
in the first case potential difference = Q / C
in the second case potential difference = Q / 2C
So potential difference becomes half .
iii ) electric field = potential diff / plate separation
in the first case electric field = Q / (d x C )
in the second case electric field = 2 Q / (d x 2C)
= Q / (d x C )
So electric field remains unchanged .
iv)
energy stored in first case = Q² / 2C
In the second case energy stored = Q² / 2x2C
so energy stored becomes half .
Answer:
Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.
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Answer:
Acceleration due to gravity, 
Explanation:
It is given that,
Mass of Pluto, 
Distance between Neptune and Pluto, 
The force of gravity is balanced by the gravitational force between Neptune and Pluto. It is given by :
So, the acceleration due to gravity at Neptune due to Pluto is 
. Hence, this is the required solution.
