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3 years ago

A swimming pool is an example of an open system. The pool loses 10,500 J

Physics

2 answers:

zaharov [31]3 years ago

8 0

Answer: A a decrease of 8000

Explanation: 10,500 - 2,500= 8000

Ivan3 years ago

4 0

Answer:

Its A

Explanation: Sure

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A race car goes from a complete stop at the start line to 150 miles per hour in 5 seconds. What is its acceleration? Show your w

qwelly [4]

Answer:

Explanation:

150/5 = 30

30mph per 1 second

3 0

3 years ago

You walk for a speed of 1.1 m/s (meters per second) for 6.0 seconds and

castortr0y [4]

Answer:

Average speed, As = 2.2 [m/s]

Explanation:

To solve these types of problems we must remember that the average of the speeds is determined by dividing the distance over time.

With the first speed and the time of 6 [s] we can calculate the distance.

V = x/t

where:

x = distance [m]

V = velocity = 1.1 [m/s]

t = time = 6 [s]

x1 = V*t

X1 = 1.1*6

X1 = 6.6 [m]

Now with the second velocity and 6 [s], we can calculate the second distance.

X2 = 3.3*6

X2 = 19.8 [m]

Now we have to calculate the average speed. The total distance is x = x1 +x2

X = 19.8 + 6.6 = 26.4 [m]

and the total time is 12 [s]

Therefore:

As = 26.4/12

As = 2.2 [m/s]

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3 years ago

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zmey [24]

D) both air temperature and medium

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3 years ago

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Apply what you know about forces to hypothesize how balanced and unbalanced forces acting on a moving car would affect the motio

rosijanka [135]

If an object has a net force acting on it, it will accelerate. The object will speed up, slow down or change direction. An unbalanced force (net force) acting on an objectchanges its speed and/or direction of motion. An unbalanced force is an unopposedforce that causes a change in motion.
thus the car would get its speed, and or direction mixed up

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3 years ago

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula: