an element can make a molecule. so technically yes.
<h2>
Answer: Diffraction</h2><h2 />
Diffraction is a characteristic phenomenon that occurs in all types of waves
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In this sense, <u>diffraction</u> happens when a wave (the light in this case) meets an obstacle or a slit .When this occurs, the light bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming <u><em>multiple patterns</em></u> with the shape of the aperture of the slit.
Note that the principal condition for the occurrence of this phenomena is that <u>the obstacle must be comparable in size (similar size) to the size of the wavelength.
</u>
<u />
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Rutherford's experiment<span> utilized positively charged alpha particles (He with a +2 charge) which were deflected by the dense inner mass (nucleus). The conclusion that could be formed from this result was that </span>atoms<span> had an inner core which contained most of the mass of an </span>atom<span> and was positively charged.</span>
Answer: The net force acting on the car 1,299.3 N.
Explanation:
Mass of the car = 710 kg
Initial velocity of the car of the ,u= 37 km/h= 10.27 m/s ![(1km\h=\frac{5}{18} m/s)](https://tex.z-dn.net/?f=%281km%5Ch%3D%5Cfrac%7B5%7D%7B18%7D%20m%2Fs%29)
Final velocity of the car,v = 120 km/h = 33.33 m/s
time taken b y car = 12.6 sec
v-u=at
![33.33m/s-10.27m/s=23.06 m/s=a(12.6 sec)](https://tex.z-dn.net/?f=33.33m%2Fs-10.27m%2Fs%3D23.06%20m%2Fs%3Da%2812.6%20sec%29)
![a = 1.83 m/s^2](https://tex.z-dn.net/?f=a%20%3D%201.83%20m%2Fs%5E2)
![Force=mass\times acceleration](https://tex.z-dn.net/?f=Force%3Dmass%5Ctimes%20acceleration)
![Force=710 kg\times 1.83 m/s^2](https://tex.z-dn.net/?f=Force%3D710%20kg%5Ctimes%201.83%20m%2Fs%5E2)
![Force=1,299.3 N](https://tex.z-dn.net/?f=Force%3D1%2C299.3%20N)
The net force acting on the car 1,299.3 N.
Answer:
Explanation:
Gravitational law states that, the force of attraction or repulsion between two masses is directly proportional to the product of the two masses and inversely proportional to the square of their distance apart.
So,
Let the masses be M1 and M2,
F ∝ M1 × M2
Let the distance apart be R
F ∝ 1 / R²
Combining the two equation
F ∝ M1•M2 / R²
G is the constant of proportional and it is called gravitational constant
F = G•M1•M2 / R²
So, to increase the gravitational force, the masses to the object must be increased and the distance apart must be reduced.
So, option c is correct
C. Both objects have large masses and are close together.