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3 years ago

What is the kinetic energy of a 1500kg car with a velocity of 72.0km/h?

1 answer:

3 0

KE=0.5 * mass* speed^2

Convert 72 km/h to m/s by dividing it by 3.6

72/3.6= 0.277778m/s

KE=0.5*1500*0.277778
= 208.3335J
= 208J

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Explanation:

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(a)

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(b)

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(c)

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$\alpha=-\frac{\tau}{I}\\\\-\frac{\mu mgR}{(\frac{2}{5}mR^2)}\\\\-\frac{2}{5}\frac{\mu g}{R}\\\\-\frac{2}{5}\frac{(0.35)(9.8)}{0.11}\\\\-77.95rad/s^2$

(d)

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equation of motion is

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(e)

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$X= V_{com,0}+ \frac{1}{2}at^2\\\\= (6.0m/s)(0.4998 s)+ 0.5(-3.43m/s^2) (0.4998 s)^2\\\\=2.57m$

(for)

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