All categories

3 years ago

What is the kinetic energy of a 1500kg car with a velocity of 72.0km/h?

1 answer:

3 0

KE=0.5 * mass* speed^2

Convert 72 km/h to m/s by dividing it by 3.6

72/3.6= 0.277778m/s

KE=0.5*1500*0.277778
= 208.3335J
= 208J

You might be interested in

The least penetrating form of radiation is _____.

vichka [17]

Alpha radiation, i just took a quiz and this was the answer, hope it helps :)

5 0

3 years ago

Pentru a scoate apă dintr‑o fântână, Ionel folosește dispozitivul reprezentat în figura 3, în care d = 20 cm și ℓ = 40 cm. Gălea

icang [17]

Answer:

no comprendo

Explanation:

6 0

3 years ago

Explain two ways of magnetising an object

Nina [5.8K]

Answer:

There are two methods generally used to magnetize permanent magnets: static magnetization and pulse magnetization.

5 0

3 years ago

Why do astronomers find it difficult to detect individual exoplanets?

Maurinko [17]

Light from the stars, because the orbits make it difficult to see them.

6 0

3 years ago

Read 2 more answers

2. Two long parallel wires each carry a current of 5.0 A directed to the east. The two wires are separated by 8.0 cm. What is th

Gre4nikov [31]

Answer:

The magnitude of magnetic field at given point = $5.33$ × $10^{-5}$ T

Explanation:

Given :

Current passing through both wires = 5.0 A

Separation between both wires = 8.0 cm

We have to find magnetic field at a point which is 5 cm from any of wires.

From biot savert law,

We know the magnetic field due to long parallel wires.

⇒ $B = \frac{\mu_{0}i }{2\pi R}$

Where $B =$ magnetic field due to long wires, $\mu_{0} =$ $4\pi \times10^{-7}$ , $R =$ perpendicular distance from wire to given point

From any one wire $R_{1} =$ 5 cm, $R_{2} =$ 3 cm

so we write,

∴ $B = B_{1} + B_{2}$

$B = \frac{\mu_{0} i}{2\pi R_{1} } + \frac{\mu_{0} i}{2\pi R_{2} }$

$B =\frac{ 4\pi \times10^{-7} \times5}{2\pi } [\frac{1}{0.03} + \frac{1}{0.05} ]$

$B = 5.33\times10^{-5} T$

Therefore, the magnitude of magnetic field at given point = $5.33\times10^{-5} T$

3 0

3 years ago