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Sergio [31]
4 years ago
12

An ionic bond is formed when _____. hints hint 1. the key to the answer is the word "ion." an ionic bond is formed when _____. o

ne atom transfers an electron to another atom atoms are subjected to radioactive isotopes both atoms are equally attractive to electrons both atoms are nonpolar both atoms are electrically neutral

Chemistry
2 answers:
Dmitriy789 [7]4 years ago
7 0

Answer : An ionic bond is formed when <u>one atom transfers an electron to another atom.</u>

Ionic bond is formed when one or more electrons from the valence shell of an atom (electropositive metal ) are completely transferred to the valence shell of another atom (electronegative non-metal).

Ionic bonds form when one atom gives up one or more electrons to another atom. It is the complete transfer of valence electron(s) between oppositely charged atoms

For example NaCl (sodium chloride ) is an ionic bond, in which valence electron from Na gets completely transferred to the valence shell of Cl and ionic bond is formed between opposite ions that is Na (positive) and Cl (negative).

Note : Ionic bond is formed between metal (electropositive element) and non-metal(electronegative element).



Paul [167]4 years ago
4 0
<h2>An ionic bond is formed when one atom transfers an electron to another atom.</h2><h3 /><h3>FURTHER EXPLANATION</h3>
  • <u>Ionic compounds</u> are compounds made up of metals and nonmetals.
  • Metals are elements that readily lose valence electrons and form positively charged ions called cations.
  • Nonmetals are atoms that readily gain electrons and form negatively charged ions called anions.
  • The electrostatic attraction between these oppositely charged ions pulls and holds them together forming the ionic compound.
<h3 /><h3>atoms are subjected to radioactive isotopes (False)</h3>

When atoms are subjected to radioactive isotopes, their number of protons or neutrons are changed. This results, not in the formation of ionic bonds, but in their transformation to another element.

<h3>both atoms are equally attractive to electrons (False)</h3>

When both have high electron affinity, the resulting compound will be molecular or covalent. Covalent compounds are formed by the sharing of electrons of two or more non-metal atoms. When all atoms have high electron affinities, they are more stable upon receiving additional electrons.  And since the natural tendency is to get to a more stable state, these atoms will resist transferring their valence electrons since that will make them more unstable. Hence, instead of complete transfer, they would share their valence electrons.

<h3>both atoms are nonpolar (False)</h3>

Ionic bonds are the forces of attraction that hold positively charged and negatively charged ions together. Nonpolar molecules result from atoms that equally share their electrons.

<h3>both atoms are electrically neutral (False)</h3>

If both atoms are electrically neutral, then they are not charged particles. Recall that the ionic bonding results from the attraction between two charged species.

LEARN MORE

  • Naming Compounds brainly.com/question/8968140
  • Ion Formation brainly.com/question/6177640
  • Nuclear Reactions brainly.com/question/9566647

Keywords: ionic bond, covalent bond, ions

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What is the gram formula mass of Ca3(PO4)2
Georgia [21]
Mass Molar of Ca_{3} (PO_4)_2
Ca = 3*40 = 120 amu
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--------------------------------------
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6 0
4 years ago
[20 Points!] The solubility product constant of calcium hydroxide is 6.5 x 10^-6. If 0.10 mol of sodium hydroxide is added to 1
sleet_krkn [62]
For Ca(OH)2, Ksp = [Ca2+][OH-]^2
You have your Ksp as 6.5 x 10^-6. Your [OH-] comes almost entirely from the 0.10 mol of NaOH, since Ca(OH)2 barely dissolves. Your [OH-] is therefore 0.10 M (since you have 1 L of solution).

6.5 x 10^-6 = [Ca2+](0.10)^2
Solve for [Ca2+]:
6.5 x 10^-6 / (0.10)^2 = [Ca2+]
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8 0
3 years ago
Calculate the theoretical density (in g/cm3) of copper (Cu), given that it has the FCC structure. The atomic weight of Cu is 63.
sasho [114]

Answer:

8.937g/cm³

Explanation:

To answer this question we need to know that, in 1 unit FCC cell you have:

Edge length = √8 * R

<em>Volume = 8√8 * R³</em>

<em>And there are 4 atoms per unit cell</em>

<em />

<em>Mass of 4 atoms in g:</em>

4 atom * (1mol / 6.022x10²³atom) * (63.55g / mol) = 4.221x10⁻²²g

<em />

<em>Volume in cm³:</em>

0.1278nm * (1x10⁻⁷cm / 1nm) = 1.278x10⁻⁸cm

Volume = 8√8 * (1.278x10⁻⁸cm)³

Volume = 4.723x10⁻²³cm³

And density is:

4.221x10⁻²²g / 4.723x10⁻²³cm³ =

<h3>8.937g/cm³</h3>

6 0
4 years ago
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