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MAXImum [283]
3 years ago
9

16. The Nile River is a(n) 16. a. Old river b. Mature river C. Young river

Chemistry
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

I think it's a old river

Explanation:

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How many atoms are in 1.50 g of Al?
Helga [31]
Question:
How many atoms are in
1.50g ofAI

Number of Mole:
Generally, the ratio within the total mass of a chemical substance and the molar mass of that chemical substance is utilized to calculate the total number of moles of the substance. The mathematical expression of the number of the mole is shown below,
n=m/M
Here, n is the total number of moles, m is the total mass and M is the total molar mass.

Answer and Explanation:


Given data

The mass of the aluminum is
m =1.50g
Note- The molar mass of the aluminum is
M=26.98g/mol
Since n=m/M
n= 1.50/26.98
n=0.0556
So the answer is A
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2 years ago
If you hold your hand over a pot of boiling water, it feels hot. Explain how the boiling water is transferring heat to your hand
FinnZ [79.3K]

Answer: by conduction, which is direct touch

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The invention of the ____ allows scientists to learn about cells.
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The Microscope allowed scientists to learn about cells.
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3 years ago
How do I create an atom with a mass of 3 and a neutral charge?
kupik [55]

Answer:

a lithium atom (Z=3, A=7 AMU) contains three protons (found from Z), three electrons (as the number of protons is equal to the number of electrons in an atom), and four neutrons (7 – 3 = 4).

Explanation:

6 0
2 years ago
If the temperature of air in gabor's lungs is 37∘c (98.6∘f), and the volume is 6l, how many moles of air n must be released by t
umka21 [38]
Missing question:
Suppose Gabor, a scuba diver, is at a depth of 15 m. Assume that:
1. The air pressure in his air tract is the same as the net water pressure at this depth. This prevents water from coming in through his nose.
2. The temperature of the air is constant (body temperature).
3. The air acts as an ideal gas.
4. Salt water has an average density of around 1.03 g/cm^3, which translates to an increase in pressure of 1.00 atm for every 10.0 m of depth below the surface. Therefore, for example, at 10.0 m, the net pressure is 2.00 atm.

T = 37°C = 310 K.
p₁ = 2,5 atm = 253,313 kPa.
p₂ = 1 atm = 101,325 kPa.
Ideal gas law: p·V = n·R·T.
n₁ = 253,313 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₁ = 0,589 mol.
n₂ = 101,325 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₂ = 0,2356 mol.
Δn = 0,589 mol - 0,2356 mol = 0,3534 mol.
5 0
4 years ago
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