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Vedmedyk [2.9K]
3 years ago
6

Mercury:3.3022×10^23 earth:5.9722×10^24 venus:4.8685×10^24 mars:6.4185×10^23

Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0

Answer:

what am i supposed to complete?

Step-by-step explanation:

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Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.
Anton [14]

Answer:

Given the graph f(x) = \frac{1}{3}x -2 and g(x) = \frac{1}{3}x + 3

We have to find the value of k;

Since, g(x) = f(x) +k

\frac{1}{3}x+3 = \frac{1}{3}x-2 +k

Subtract \frac{1}{3}x from both sides we get;

3 = -2 +k

Add 2 to both sides we get;

3+2 = -2 +k +2

Simplify:

5 = k

or

k = 5

Therefore, the value of k = 5


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3 years ago
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Which statement is true about the product of 5/12 x 7?
nataly862011 [7]

Answer:

B

Step-by-step explanation:

because the denominator of fraction, 5/12 ,is greater than both the numerator and the multiplier which is 7

6 0
3 years ago
Round 768 to the nearest 10
algol13
770 because the 1 is higher than 5 so you round up
6 0
3 years ago
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Audrey gave a 0.90 tip to a waitress for serving a meal costing $6.00. what percent of the bill was her tip?
maw [93]

Answer:

<u>15%</u> percent of the bill was her tip.

Step-by-step explanation:

Given:

Audrey gave a $0.90 tip to a waitress for serving a meal costing $6.00.

Now, to find the percent of the bill was her tip.

The bill was = $6.00.

The tip she gave = $0.90.

Now, to get the percent of the bill was her tip:

\frac{The\ tip}{The\ bill}\times 100

=\frac{0.90}{6.00} \times 100

=0.15\times 100

=15\%.

Therefore, 15% percent of the bill was her tip.

7 0
4 years ago
Solve tan 10 - tan 50 +tan 70 with trigonometry.
Jobisdone [24]
Below is the solution, I hope it helps.

  <span>i) tan(70) - tan(50) = tan(60 + 10) - tan(60 - 10) 

= {tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)} 

ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: 

= 8*tan(10)/{1 - 3*tan²(10)} 

iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) 

= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} 

= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} 

= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} 

= 3*tan(30) = 3*(1/√3) = √3 [Proved] 

[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, 
{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
7 0
3 years ago
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