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3 years ago

In which pair do both atoms have one electron only in an s orbital in their ground states?

1 answer:

4 0

The answer to this is letter D.

Chromium's electron configuration is 1s2 2s2 2p6 3s2 3p6 3d5 4s1, where the last electron is in the s orbital with only 1. As for Li, it is found in the group 1 metals, and it is a fact that all elements under this group has the their last electron to be in the s orbital with only one electron in their outermost shell.

The electron configuration associated with the lowest energy level of the atom is referred to as ground state and each electron ion is in the lowest energy level possible. When the moment comes that electrons go into a higher level of energy, that is what we call the excited state.

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Balancing chemical equations (8 questions)

sweet [91]

Sorry it’s messy, hope this helps :]

4 0

2 years ago

How much HCI exists in 275 mL of 0.83 M solution of HCI? Answer in units of mol.

zubka84 [21]

Answer:

0.22825mol HCl

Explanation:

$M=\frac{moles}{liters} \\$

$0.83M HCl = \frac{x(mol)}{0.275L}$

1. Cross multiply!

$\frac{0.83M}{1} =\frac{x}{0.275L}$

$x = 0.22825 mol HCl$

7 0

3 years ago

The voltage in a flashlight bulb is 6.0 volts and has a resistance of 24 ohms. Calculate the current

taurus [48]

Answer:

Thanks for the points

Explanation:

5 0

3 years ago

Read 2 more answers

Write the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each:

Sladkaya [172]

Answer:

Part A:

Charge is $P^{3-}$

Configuration is $1s^2 2s^22p^63s^23p^6$

Part B:

Charge is $Mg^{2+}$

Configuration is $1s^2 2s^22p^6$

Part C:

Charge is $Se^{2-}$

Configuration is $1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6$

Explanation:

Monatomic ions:

These ions consist of only one atom. If they have more than one atom then they are poly atomic ions.

Examples of Mono Atomic ions: $Na^+, Cl^-, Ca^2^+$

Part A:

For P:

Phosphorous (P) has 15 electrons so it require 3 more electrons to stabilize itself.

Charge is $P^{3-}$

Full ground-state electron configuration of the mono atomic ion:

$1s^2 2s^22p^63s^23p^6$

Part B:

For Mg:

Magnesium (Mg) has 12 electrons so it requires 2 electrons to lose to achieve stable configuration.

Charge is $Mg^{2+}$

Full ground-state electron configuration of the mono atomic ion:

$1s^2 2s^22p^6$

Part C:

For Se:

Selenium (Se) has 34 electrons and requires two electrons to be stable.

Charge is $Se^{2-}$

Full ground-state electron configuration of the mono atomic ion:

$1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6$

8 0

4 years ago

If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T

Veronika [31]

Answer:

$m_{MnO_2}=21.2gMnO_2$

Explanation:

Hello,

In this case, given the balanced reaction:

$2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O$

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

$m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-} *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2$

Best regards.

5 0

4 years ago