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White raven [17]
3 years ago
8

1.0 L of .50 M of NaCl

Chemistry
1 answer:
Vlada [557]3 years ago
8 0

Explanation:

From the given parameters we can calculate the mass and number of moles in this amount of solution of NaCl

Volume of solution = 1L

Molarity = 0.5M

We know that this is a solution. The molarity indicates that amount of solute was dissolved in a solvent.

To find the number of moles of solution;

Number of moles = molarity x volume

molarity is the the number of moles of solute in a solution.

 input the variables;

    Number of moles = 0.5 x 1 = 0.5moles

Mass of NaCl:

  Mass of NaCl = number of moles x molar mass

molar mass of NaCl = 58.54g/mol

  Mass of NaCl = 0.5 x 58.54 = 29.27g

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

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Write the balanced chemical equation between H2SO4 and KOH in aqueous solution. This is called a neutralization reaction and wil
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Answer:

0.166M

Explanation:

In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:

<em>Moles H2SO4:</em>

0.650L * (0.430mol /L) = 0.2795moles H2SO4

<em>Moles KOH:</em>

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Moles of sulfuric acid that reacts with 0.144 moles of KOH are:

0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.

And remain:

0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.

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Molar concentration of sulfuric acid:

0.2075 moles of H2SO4 / 1.25L =

<h3>0.166M</h3>
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What are the conditions to liquefy a gas ?
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How much heat energy is required to melt 75g of ice at 0°C?
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The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol. This means for every mole of ice we melt we must apply 6.02 kj of heat. We can calculate the heat needed with the following equation:

Q = N x ΔH

where:

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N  = moles  

ΔH  = enthalpy

In this problem we would like to calculate the heat needed to melt 35 grams of ice at 0 °C. This problem can be broken into three steps:


1. Calculate moles of water

2. multiply by the enthalpy of fusion

3. Convert kJ to J.


Step 1 : Calculate moles of water

[ 75g ] x (\frac{1 mol}{18.02g} ) =

Step 2 : Multiply by enthalpy of fusion

Q = N × ΔH  = <em> [ Step 1 Answer ]</em> ×  6.02 =

Step 3 : Convert kJ to J

[ Step 2 Answer ] x (\frac{1000j}{1kJ} ) =

Finally rounding to 2 sig figs (since 34°C has two sig figs) we get


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3 years ago
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