All categories

3 years ago

1.0 L of .50 M of NaCl

Chemistry

1 answer:

Vlada [557]3 years ago

8 0

Explanation:

From the given parameters we can calculate the mass and number of moles in this amount of solution of NaCl

Volume of solution = 1L

Molarity = 0.5M

We know that this is a solution. The molarity indicates that amount of solute was dissolved in a solvent.

To find the number of moles of solution;

Number of moles = molarity x volume

molarity is the the number of moles of solute in a solution.

input the variables;

Number of moles = 0.5 x 1 = 0.5moles

Mass of NaCl:

Mass of NaCl = number of moles x molar mass

molar mass of NaCl = 58.54g/mol

Mass of NaCl = 0.5 x 58.54 = 29.27g

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

You might be interested in

If you mix 50mL of 0.1 M TRIS acid with 60 mL of0.2 M TRIS base, what will be the resulting pH?

Katyanochek1 [597]

Answer: The pH of resulting solution is 8.7

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

For TRIS acid:

Molarity of TRIS acid solution = 0.1 M

Volume of solution = 50 mL

Putting values in above equation, we get:

$0.1M=\frac{\text{Moles of TRIS acid}\times 1000}{50mL}\\\\\text{Moles of TRIS acid}=0.005mol$

For TRIS base:

Molarity of TRIS base solution = 0.2 M

Volume of solution = 60 mL

Putting values in above equation, we get:

$0.2M=\frac{\text{Moles of TRIS base}\times 1000}{60mL}\\\\\text{Moles of TRIS base}=0.012mol$

Volume of solution = 50 + 60 = 110 mL = 0.11 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

$pH=pK_a+\log(\frac{[\text{TRIS base}]}{[\text{TRIS acid}]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of TRIS acid = 8.3

$[\text{TRIS acid}]=\frac{0.005}{0.11}$

$[\text{TRIS base}]=\frac{0.012}{0.11}$

pH = ?

Putting values in above equation, we get:

$pH=8.3+\log(\frac{0.012/0.11}{0.005/0.11})\\\\pH=8.7$

Hence, the pH of resulting solution is 8.7

6 0

4 years ago

The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate

Cloud [144]

Answer : The $\Delta G$ for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,

$Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)$

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : $Cu\rightarrow Cu^{2+}+2e^-$

Reduction : $2Ag^++2e^-\rightarrow 2Ag$

Now we have to calculate the Gibbs free energy.

Formula used :

$\Delta G^o=-nFE^o$

where,

$\Delta G^o$ = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

$E^o$ = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

$\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole$

Therefore, the $\Delta G$ for this reaction is, -88780 J/mole.

7 0

4 years ago

Which of these statements is most likely correct about a weak nuclear force?

Tatiana [17]

It binds electrons and protons!

5 0

3 years ago

Read 2 more answers

The Tin Pan Alley era lasted from 1950 to 1967. a. true b. false

fenix001 [56]

I think false is the answer .if wrong correct meeee

7 0

3 years ago

If a quadrilateral has three angels measuring 60, 45 and 100 find the measure of the fourth angel

Nina [5.8K]

The sum of angels of a quadrilateral is equal to 360°.

∠A = 360 - (60 + 45 + 100) = 155

7 0

3 years ago