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Ahat [919]
3 years ago
10

A radioactive nucleus emits a beta particle, then the parent and daughter nuclei are

Chemistry
2 answers:
Nana76 [90]3 years ago
3 0

Answer:

isobars

Explanation:

How?

  • A radioactive nucleus emits beta particle(Like uranium,radium)
  • So the mass numbers are same for daughter nuclei .
  • They have different atomic numbes .

So they are isobars

slega [8]3 years ago
3 0

Answer:

⇢Isobars⇢Isobars

Explanation:

⇢Isobars⇢Isobars

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Answer is: (2) Chemical energy is converted to electrical energy.

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In galvanic cell, specie (for example zinc and zinc cations) from one half-cell, lose electrons (oxidation) and species from the other half-cell (for example copper and copper cations) gain electrons (reduction).

Oxidation on the zinc anode: Zn(s) → Zn²⁺(aq) + 2e⁻.

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8 0
4 years ago
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Which of the following compounds is not possible?
neonofarm [45]

Answer:

C

Explanation:

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4 0
3 years ago
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You can count it by yourself using formula

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5 0
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How will the candle contributes to the pressure and temperature of gases inside the glass?
Tems11 [23]
How will the candle contributes to the pressure and temperature of gases inside the glass?

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7 0
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A balloon containing helium gas expands from 230
Anit [1.1K]

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final  moles of the gas is 14.2 × </em></u>10^{-4}<u><em> moles.</em></u>

Explanation:

Given:

Initial volume (V_{1}) = 230 ml

Final volume (V_{2}) = 860 ml

Initial moles (n_{1}) = 3.8 ×10^{-4} moles

To find:

Final moles (n_{2})

We know;

According to the ideal gas equation;

    P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of the moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

So;

    V ∝ n

\frac{V_{1} }{V_{2} } = \frac{n_{1} }{n_{2} }

where,

(V_{1}) represents the initial volume of the gas

(V_{2}) represents the final volume of the gas

(n_{1}) represents the initial  moles of the gas

(n_{2}) represents the final moles of the gas

Substituting the above values;

   \frac{230}{860} = \frac{3.8 * 10^-4}{n_{2} }

  n_{2} = 14.2 × 10^{-4} moles

<u><em>Therefore the final  moles of the gas is 14.2 × </em></u>10^{-4}<u><em> moles.</em></u>

7 0
3 years ago
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