The answer is acidity, because pH indicators help indicate the H+ or OH- concentration in a solution. H+ concentrations create acids, and OH- make bases. pH indicators don’t indicate any of the other answers in the question, so the answer is Acidity.
Answer:
B. pour the reagent into a small beaker before using it
Explanation:
Let's explore all the mentioned practice
A. Leftover reagents should not be discarded in the sink but discarded according to the disposal method present in the safety data sheet (SDS) of the chemical.
B. Reagents should be poured in a clean beaker for use to avoid contamination in the original reagent bottle
C. This is not a good practice, as the plastic pipet tends to contain some impurity in its tip.
D. This is also a bad practice. Firstly, a reagent should be taken according to the need. If there is leftover, it should be discarded as it most probably contains contamination in it
A solution is the answer to a problem
Answer:
Part A: 2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B: -r = K*[N₂O]²
Part C: K= k1*k2
Explanation:
Part A
To do the balance chemical question for the overall chemical reaction, we must sum the reaction of the steps, eliminating the intermediaries, which are the compounds that have the same amount both at reactants and products (bolded).
N₂O(g) ⇄ N₂(g) + O(g)
N₂O(g) + O(g) ⇄ N₂(g) + O₂(g)
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2N₂O(g) + O(g) ⇄ 2N₂(g) + O(g) + O₂(g)
2N₂O(g) ⇄ 2N₂(g) + O₂(g)
Part B
The velocity of the reaction (r) can be calculated based on the reactants or based on the products. Let's do it based on the disappearing of the reactant. Because it is disappearing, the variation at its concentration must be negative, so the rate will be negative.
Let's suppose its an elementary reaction, so, the concentration of the reactant must be elevated by its coefficient. And let's call the overall rate constant as K:
-r = K*[N₂O]²
Part C
Because the steps were summed, and the reactions were not multiplied by a constant or inverted, the constant K is just the multiplication of the constants of the steps:
K= k1*k2
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Hope this helps :)
